Luacháil (complex solution)
a=26bcm\text{ and }26bcm=19mc^{2}\text{ and }19mc^{2}=42cm
Réitigh do m.
\left\{\begin{matrix}m\in \mathrm{R}\text{, }&a=0\text{ and }c=0\\m=0\text{, }&a=0\text{ and }\left(b=0\text{ or }c\neq 0\right)\\m=\frac{19a}{1764}\text{, }&c=\frac{42}{19}\text{ and }b=\frac{21}{13}\end{matrix}\right.
Réitigh do c.
\left\{\begin{matrix}c\in \mathrm{R}\text{, }&a=0\text{ and }m=0\\c=0\text{, }&a=0\text{ and }\left(m\neq 0\text{ or }b=0\right)\\c=\frac{a}{26bm}\text{, }&b=\frac{21}{13}\text{ and }a=\frac{1764m}{19}\text{ and }m\neq 0\end{matrix}\right.
Tráth na gCeist
Algebra
5 fadhbanna cosúil le:
a = 26 cm b = 19 cm c = 42 cm
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