Réitigh a+bsqrt{2}=3(1-sqrt{2})+4sqrt{2}

$$a + b \sqrt { 2 } = 3 ( 1 - \sqrt { 2 } ) + 4 \sqrt { 2 }$$

Réitigh do b.

$$b=-\frac{\sqrt{2}\left(a-\sqrt{2}-3\right)}{2}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an t-airí dáileach chun 3 a mhéadú faoi 1-\sqrt{2}.

$$a+b\sqrt{2}=3-3\sqrt{2}+4\sqrt{2}$$

Comhcheangail -3\sqrt{2} agus 4\sqrt{2} chun \sqrt{2} a fháil.

$$a+b\sqrt{2}=3+\sqrt{2}$$

Bain a ón dá thaobh.

$$b\sqrt{2}=3+\sqrt{2}-a$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\sqrt{2}b=-a+\sqrt{2}+3$$

Roinn an dá thaobh faoi \sqrt{2}.

$$\frac{\sqrt{2}b}{\sqrt{2}}=\frac{-a+\sqrt{2}+3}{\sqrt{2}}$$

Má roinntear é faoi \sqrt{2} cuirtear an iolrúchán faoi \sqrt{2} ar ceal.

$$b=\frac{-a+\sqrt{2}+3}{\sqrt{2}}$$

Roinn 3+\sqrt{2}-a faoi \sqrt{2}.

$$b=\frac{\sqrt{2}\left(-a+\sqrt{2}+3\right)}{2}$$

Réitigh do a.

$$a=-\sqrt{2}\left(b-1\right)+3$$