Réitigh W=-1/2t^2+(14+2a)t-96a+48

$$W = - \frac { 1 } { 2 } t ^ { 2 } + ( 14 + 2 a ) t - 96 a + 48$$

Réitigh do a. (complex solution)

$$\left\{\begin{matrix}a=-\frac{96-2W+28t-t^{2}}{4\left(t-48\right)}\text{, }&t\neq 48\\a\in \mathrm{C}\text{, }&W=-432\text{ and }t=48\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an t-airí dáileach chun 14+2a a mhéadú faoi t.

$$W=-\frac{1}{2}t^{2}+14t+2at-96a+48$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$-\frac{1}{2}t^{2}+14t+2at-96a+48=W$$

Cuir \frac{1}{2}t^{2} leis an dá thaobh.

$$14t+2at-96a+48=W+\frac{1}{2}t^{2}$$

Bain 14t ón dá thaobh.

$$2at-96a+48=W+\frac{1}{2}t^{2}-14t$$

Bain 48 ón dá thaobh.

$$2at-96a=W+\frac{1}{2}t^{2}-14t-48$$

Comhcheangail na téarmaí ar fad ina bhfuil a.

$$\left(2t-96\right)a=W+\frac{1}{2}t^{2}-14t-48$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(2t-96\right)a=\frac{t^{2}}{2}+W-14t-48$$

Roinn an dá thaobh faoi 2t-96.

$$\frac{\left(2t-96\right)a}{2t-96}=\frac{\frac{t^{2}}{2}+W-14t-48}{2t-96}$$

Má roinntear é faoi 2t-96 cuirtear an iolrúchán faoi 2t-96 ar ceal.

$$a=\frac{\frac{t^{2}}{2}+W-14t-48}{2t-96}$$

Roinn W+\frac{t^{2}}{2}-14t-48 faoi 2t-96.

$$a=\frac{t^{2}-28t+2W-96}{4\left(t-48\right)}$$

Réitigh do a.

$$\left\{\begin{matrix}a=-\frac{96-2W+28t-t^{2}}{4\left(t-48\right)}\text{, }&t\neq 48\\a\in \mathrm{R}\text{, }&W=-432\text{ and }t=48\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an t-airí dáileach chun 14+2a a mhéadú faoi t.

$$W=-\frac{1}{2}t^{2}+14t+2at-96a+48$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$-\frac{1}{2}t^{2}+14t+2at-96a+48=W$$

Cuir \frac{1}{2}t^{2} leis an dá thaobh.

$$14t+2at-96a+48=W+\frac{1}{2}t^{2}$$

Bain 14t ón dá thaobh.

$$2at-96a+48=W+\frac{1}{2}t^{2}-14t$$

Bain 48 ón dá thaobh.

$$2at-96a=W+\frac{1}{2}t^{2}-14t-48$$

Comhcheangail na téarmaí ar fad ina bhfuil a.

$$\left(2t-96\right)a=W+\frac{1}{2}t^{2}-14t-48$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(2t-96\right)a=\frac{t^{2}}{2}+W-14t-48$$

Roinn an dá thaobh faoi 2t-96.

$$\frac{\left(2t-96\right)a}{2t-96}=\frac{\frac{t^{2}}{2}+W-14t-48}{2t-96}$$

Má roinntear é faoi 2t-96 cuirtear an iolrúchán faoi 2t-96 ar ceal.

$$a=\frac{\frac{t^{2}}{2}+W-14t-48}{2t-96}$$

Roinn W+\frac{t^{2}}{2}-14t-48 faoi 2t-96.

$$a=\frac{t^{2}-28t+2W-96}{4\left(t-48\right)}$$

Réitigh do W.

$$W=2at-\frac{t^{2}}{2}+14t-96a+48$$

Céimeanna Réitigh

Úsáid an t-airí dáileach chun 14+2a a mhéadú faoi t.

$$W=-\frac{1}{2}t^{2}+14t+2at-96a+48$$