Réitigh V=4pisqrt{x/4},s

$$V = 4 \pi \sqrt { \frac { x } { 4 } } , s$$

Réitigh do x.

$$x=\frac{\left(\frac{V}{\pi }\right)^{2}}{4}$$

$$V\geq 0$$

Céimeanna chun cothromóidí fréimhe a réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$4\pi \sqrt{\frac{x}{4}}=V$$

Roinn an dá thaobh faoi 4\pi .

$$\frac{4\pi \sqrt{\frac{1}{4}x}}{4\pi }=\frac{V}{4\pi }$$

Má roinntear é faoi 4\pi cuirtear an iolrúchán faoi 4\pi ar ceal.

$$\sqrt{\frac{1}{4}x}=\frac{V}{4\pi }$$

Cearnaigh an dá thaobh den chothromóid.

$$\frac{1}{4}x=\frac{V^{2}}{16\pi ^{2}}$$

Iolraigh an dá thaobh faoi 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{V^{2}}{\frac{1}{4}\times 16\pi ^{2}}$$

Má roinntear é faoi \frac{1}{4} cuirtear an iolrúchán faoi \frac{1}{4} ar ceal.

$$x=\frac{V^{2}}{\frac{1}{4}\times 16\pi ^{2}}$$

Roinn \frac{V^{2}}{16\pi ^{2}} faoi \frac{1}{4} trí \frac{V^{2}}{16\pi ^{2}} a mhéadú faoi dheilín \frac{1}{4}.

$$x=\frac{V^{2}}{4\pi ^{2}}$$

Réitigh do V. (complex solution)

$$V=2\pi \sqrt{x}$$

Réitigh do x. (complex solution)

$$x=\frac{\left(\frac{V}{\pi }\right)^{2}}{4}$$

$$|\frac{arg(V^{2})}{2}-arg(V)|<\pi \text{ or }V=0$$

Réitigh do V.

$$V=2\pi \sqrt{x}$$

$$x\geq 0$$