Réitigh T=2pisqrt{L/a}

$$T = 2 \pi \sqrt { \frac { L } { a } }$$

Réitigh do L.

$$L=\frac{a\times \left(\frac{T}{\pi }\right)^{2}}{4}$$

$$T\geq 0\text{ and }a\neq 0$$

Céimeanna chun cothromóidí fréimhe a réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$2\pi \sqrt{\frac{L}{a}}=T$$

Roinn an dá thaobh faoi 2\pi .

$$\frac{2\pi \sqrt{\frac{1}{a}L}}{2\pi }=\frac{T}{2\pi }$$

Má roinntear é faoi 2\pi cuirtear an iolrúchán faoi 2\pi ar ceal.

$$\sqrt{\frac{1}{a}L}=\frac{T}{2\pi }$$

Cearnaigh an dá thaobh den chothromóid.

$$\frac{1}{a}L=\frac{T^{2}}{4\pi ^{2}}$$

Roinn an dá thaobh faoi a^{-1}.

$$\frac{\frac{1}{a}La}{1}=\frac{T^{2}}{4\pi ^{2}\times \frac{1}{a}}$$

Má roinntear é faoi a^{-1} cuirtear an iolrúchán faoi a^{-1} ar ceal.

$$L=\frac{T^{2}}{4\pi ^{2}\times \frac{1}{a}}$$

Roinn \frac{T^{2}}{4\pi ^{2}} faoi a^{-1}.

$$L=\frac{aT^{2}}{4\pi ^{2}}$$

Réitigh do T.

$$T=2\pi \sqrt{\frac{L}{a}}$$

$$\left(L\geq 0\text{ and }a>0\right)\text{ or }\left(L\leq 0\text{ and }a<0\right)$$