Réitigh do R.
\left\{\begin{matrix}R=\frac{100p}{S\Phi T^{2}}\text{, }&T\neq 0\text{ and }S\neq 0\text{ and }\Phi \neq 0\\R\in \mathrm{R}\text{, }&p=0\text{ and }\Phi =0\text{ and }T\neq 0\text{ and }S\neq 0\end{matrix}\right.
Réitigh do S.
\left\{\begin{matrix}S=\frac{100p}{R\Phi T^{2}}\text{, }&p\neq 0\text{ and }T\neq 0\text{ and }\Phi \neq 0\text{ and }R\neq 0\\S\neq 0\text{, }&\left(\Phi =0\text{ or }R=0\right)\text{ and }p=0\text{ and }T\neq 0\end{matrix}\right.
Tráth na gCeist
Linear Equation
5 fadhbanna cosúil le:
R \Phi = \frac { p \times 100 } { T \times S T }
Roinn
Cóipeáladh go dtí an ghearrthaisce
R\Phi ST^{2}=p\times 100
Méadaigh an dá thaobh den chothromóid faoi ST^{2}.
RS\Phi T^{2}=100p
Athordaigh na téarmaí.
S\Phi T^{2}R=100p
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{S\Phi T^{2}R}{S\Phi T^{2}}=\frac{100p}{S\Phi T^{2}}
Roinn an dá thaobh faoi S\Phi T^{2}.
R=\frac{100p}{S\Phi T^{2}}
Má roinntear é faoi S\Phi T^{2} cuirtear an iolrúchán faoi S\Phi T^{2} ar ceal.
R\Phi ST^{2}=p\times 100
Ní féidir leis an athróg S a bheith comhionann le 0 toisc nach bhfuil an roinnt faoi nialas sainithe. Méadaigh an dá thaobh den chothromóid faoi ST^{2}.
RS\Phi T^{2}=100p
Athordaigh na téarmaí.
R\Phi T^{2}S=100p
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{R\Phi T^{2}S}{R\Phi T^{2}}=\frac{100p}{R\Phi T^{2}}
Roinn an dá thaobh faoi R\Phi T^{2}.
S=\frac{100p}{R\Phi T^{2}}
Má roinntear é faoi R\Phi T^{2} cuirtear an iolrúchán faoi R\Phi T^{2} ar ceal.
S=\frac{100p}{R\Phi T^{2}}\text{, }S\neq 0
Ní féidir leis an athróg S a bheith comhionann le 0.
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