Réitigh Q=K*A*Deltaθ/l=

$$Q = \frac { K \cdot A \cdot \Delta \theta } { l } =$$

Réitigh do A. (complex solution)

$$\left\{\begin{matrix}A=\frac{Ql}{K\Delta \theta }\text{, }&\theta \neq 0\text{ and }\Delta \neq 0\text{ and }K\neq 0\text{ and }l\neq 0\\A\in \mathrm{C}\text{, }&\left(\theta =0\text{ or }\Delta =0\text{ or }K=0\right)\text{ and }Q=0\text{ and }l\neq 0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi l.

$$Ql=KA\Delta \theta$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$KA\Delta \theta =Ql$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$K\Delta \theta A=Ql$$

Roinn an dá thaobh faoi K\Delta \theta .

$$\frac{K\Delta \theta A}{K\Delta \theta }=\frac{Ql}{K\Delta \theta }$$

Má roinntear é faoi K\Delta \theta cuirtear an iolrúchán faoi K\Delta \theta ar ceal.

$$A=\frac{Ql}{K\Delta \theta }$$

Réitigh do K. (complex solution)

$$\left\{\begin{matrix}K=\frac{Ql}{A\Delta \theta }\text{, }&\theta \neq 0\text{ and }\Delta \neq 0\text{ and }A\neq 0\text{ and }l\neq 0\\K\in \mathrm{C}\text{, }&\left(\theta =0\text{ or }\Delta =0\text{ or }A=0\right)\text{ and }Q=0\text{ and }l\neq 0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi l.

$$Ql=KA\Delta \theta$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$KA\Delta \theta =Ql$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$A\Delta \theta K=Ql$$

Roinn an dá thaobh faoi A\Delta \theta .

$$\frac{A\Delta \theta K}{A\Delta \theta }=\frac{Ql}{A\Delta \theta }$$

Má roinntear é faoi A\Delta \theta cuirtear an iolrúchán faoi A\Delta \theta ar ceal.

$$K=\frac{Ql}{A\Delta \theta }$$

Réitigh do A.

$$\left\{\begin{matrix}A=\frac{Ql}{K\Delta \theta }\text{, }&\theta \neq 0\text{ and }\Delta \neq 0\text{ and }K\neq 0\text{ and }l\neq 0\\A\in \mathrm{R}\text{, }&\left(\theta =0\text{ or }\Delta =0\text{ or }K=0\right)\text{ and }Q=0\text{ and }l\neq 0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi l.

$$Ql=KA\Delta \theta$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$KA\Delta \theta =Ql$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$K\Delta \theta A=Ql$$

Roinn an dá thaobh faoi K\Delta \theta .

$$\frac{K\Delta \theta A}{K\Delta \theta }=\frac{Ql}{K\Delta \theta }$$

Má roinntear é faoi K\Delta \theta cuirtear an iolrúchán faoi K\Delta \theta ar ceal.

$$A=\frac{Ql}{K\Delta \theta }$$

Réitigh do K.

$$\left\{\begin{matrix}K=\frac{Ql}{A\Delta \theta }\text{, }&\theta \neq 0\text{ and }\Delta \neq 0\text{ and }A\neq 0\text{ and }l\neq 0\\K\in \mathrm{R}\text{, }&\left(\theta =0\text{ or }\Delta =0\text{ or }A=0\right)\text{ and }Q=0\text{ and }l\neq 0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi l.

$$Ql=KA\Delta \theta$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$KA\Delta \theta =Ql$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$A\Delta \theta K=Ql$$

Roinn an dá thaobh faoi A\Delta \theta .

$$\frac{A\Delta \theta K}{A\Delta \theta }=\frac{Ql}{A\Delta \theta }$$

Má roinntear é faoi A\Delta \theta cuirtear an iolrúchán faoi A\Delta \theta ar ceal.

$$K=\frac{Ql}{A\Delta \theta }$$