Réitigh P(x)=3x^2-10x-6quadD(x)=x-3

$$P ( x ) = 3 x ^ { 2 } - 10 x - 6 \quad D ( x ) = x - 3$$

Réitigh do D.

$$D=\frac{x}{2}-\frac{11}{6}+\frac{1}{2x}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 3x^{2} ón dá thaobh.

$$-10x-6Dx=x-3-3x^{2}$$

Cuir 10x leis an dá thaobh.

$$-6Dx=x-3-3x^{2}+10x$$

Comhcheangail x agus 10x chun 11x a fháil.

$$-6Dx=11x-3-3x^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-6x\right)D=-3x^{2}+11x-3$$

Roinn an dá thaobh faoi -6x.

$$\frac{\left(-6x\right)D}{-6x}=\frac{-3x^{2}+11x-3}{-6x}$$

Má roinntear é faoi -6x cuirtear an iolrúchán faoi -6x ar ceal.

$$D=\frac{-3x^{2}+11x-3}{-6x}$$

Roinn 11x-3-3x^{2} faoi -6x.

$$D=\frac{x}{2}-\frac{11}{6}+\frac{1}{2x}$$

Réitigh do x. (complex solution)

$$x=\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

$$x=-\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

Réitigh do x.

$$x=\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}$$

$$x=-\frac{\sqrt{36D^{2}+132D+85}}{6}+D+\frac{11}{6}\text{, }D\leq -\frac{17}{6}\text{ or }D\geq -\frac{5}{6}$$