Réitigh P=acos5θ

$$P = a \cos 5 \theta$$

Réitigh do a.

$$\left\{\begin{matrix}a=\frac{P}{\cos(5\theta )}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\frac{\pi n_{1}}{5}+\frac{\pi }{10}\\a\in \mathrm{R}\text{, }&P=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =\frac{\pi n_{1}}{5}+\frac{\pi }{10}\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$a\cos(5\theta )=P$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\cos(5\theta )a=P$$

Roinn an dá thaobh faoi \cos(5\theta ).

$$\frac{\cos(5\theta )a}{\cos(5\theta )}=\frac{P}{\cos(5\theta )}$$

Má roinntear é faoi \cos(5\theta ) cuirtear an iolrúchán faoi \cos(5\theta ) ar ceal.

$$a=\frac{P}{\cos(5\theta )}$$

Réitigh do P.

$$P=a\cos(5\theta )$$