Réitigh F=6.667*10^-11Nm/kg^2

$$F = 6.667 \times 10 ^ { - 11 } Nm / kg ^ { 2 }$$

Réitigh do N.

$$\left\{\begin{matrix}N=\frac{100000000000000Fk}{6667mg^{2}}\text{, }&g\neq 0\text{ and }m\neq 0\text{ and }k\neq 0\\N\in \mathrm{R}\text{, }&\left(g=0\text{ or }m=0\right)\text{ and }F=0\text{ and }k\neq 0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi k.

$$Fk=6.667\times 10^{-11}Nmg^{2}$$

Ríomh cumhacht 10 de -11 agus faigh \frac{1}{100000000000}.

$$Fk=6.667\times \frac{1}{100000000000}Nmg^{2}$$

Méadaigh 6.667 agus \frac{1}{100000000000} chun \frac{6667}{100000000000000} a fháil.

$$Fk=\frac{6667}{100000000000000}Nmg^{2}$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$\frac{6667}{100000000000000}Nmg^{2}=Fk$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\frac{6667mg^{2}}{100000000000000}N=Fk$$

Roinn an dá thaobh faoi \frac{6667}{100000000000000}mg^{2}.

$$\frac{100000000000000\times \frac{6667mg^{2}}{100000000000000}N}{6667mg^{2}}=\frac{100000000000000Fk}{6667mg^{2}}$$

Má roinntear é faoi \frac{6667}{100000000000000}mg^{2} cuirtear an iolrúchán faoi \frac{6667}{100000000000000}mg^{2} ar ceal.

$$N=\frac{100000000000000Fk}{6667mg^{2}}$$

Réitigh do F.

$$F=\frac{6667Nmg^{2}}{100000000000000k}$$

$$k\neq 0$$