Réitigh do A. (complex solution)
\left\{\begin{matrix}A=\frac{C_{e}}{Th_{C}t\Delta }\text{, }&T\neq 0\text{ and }\Delta \neq 0\text{ and }t\neq 0\text{ and }h_{C}\neq 0\\A\in \mathrm{C}\text{, }&\left(T=0\text{ or }\Delta =0\text{ or }t=0\text{ or }h_{C}=0\right)\text{ and }C_{e}=0\end{matrix}\right.
Réitigh do A.
\left\{\begin{matrix}A=\frac{C_{e}}{Th_{C}t\Delta }\text{, }&T\neq 0\text{ and }\Delta \neq 0\text{ and }t\neq 0\text{ and }h_{C}\neq 0\\A\in \mathrm{R}\text{, }&\left(T=0\text{ or }\Delta =0\text{ or }t=0\text{ or }h_{C}=0\right)\text{ and }C_{e}=0\end{matrix}\right.
Réitigh do C_e.
C_{e}=ATh_{C}t\Delta
Tráth na gCeist
Linear Equation
C _ { e } = h _ { C } A t \Delta T
Roinn
Cóipeáladh go dtí an ghearrthaisce
h_{C}At\Delta T=C_{e}
Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.
Th_{C}t\Delta A=C_{e}
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{Th_{C}t\Delta A}{Th_{C}t\Delta }=\frac{C_{e}}{Th_{C}t\Delta }
Roinn an dá thaobh faoi h_{C}t\Delta T.
A=\frac{C_{e}}{Th_{C}t\Delta }
Má roinntear é faoi h_{C}t\Delta T cuirtear an iolrúchán faoi h_{C}t\Delta T ar ceal.
h_{C}At\Delta T=C_{e}
Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.
Th_{C}t\Delta A=C_{e}
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{Th_{C}t\Delta A}{Th_{C}t\Delta }=\frac{C_{e}}{Th_{C}t\Delta }
Roinn an dá thaobh faoi h_{C}t\Delta T.
A=\frac{C_{e}}{Th_{C}t\Delta }
Má roinntear é faoi h_{C}t\Delta T cuirtear an iolrúchán faoi h_{C}t\Delta T ar ceal.
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