Réitigh 7x-5y(x+36y)=7

$$7x-5y(x+36y)=7$$

Réitigh do x.

$$x=\frac{180y^{2}+7}{7-5y}$$

$$y\neq \frac{7}{5}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh -1 agus 5 chun -5 a fháil.

$$7x-5y\left(x+36y\right)=7$$

Úsáid an t-airí dáileach chun -5y a mhéadú faoi x+36y.

$$7x-5yx-180y^{2}=7$$

Cuir 180y^{2} leis an dá thaobh.

$$7x-5yx=7+180y^{2}$$

Comhcheangail na téarmaí ar fad ina bhfuil x.

$$\left(7-5y\right)x=7+180y^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(7-5y\right)x=180y^{2}+7$$

Roinn an dá thaobh faoi -5y+7.

$$\frac{\left(7-5y\right)x}{7-5y}=\frac{180y^{2}+7}{7-5y}$$

Má roinntear é faoi -5y+7 cuirtear an iolrúchán faoi -5y+7 ar ceal.

$$x=\frac{180y^{2}+7}{7-5y}$$

Réitigh do y. (complex solution)

$$y=\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

$$y=-\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

Réitigh do y.

$$y=\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}$$

$$y=-\frac{\sqrt{25x^{2}+5040x-5040}}{360}-\frac{x}{72}\text{, }x\geq \frac{12\sqrt{1799}-504}{5}\text{ or }x\leq \frac{-12\sqrt{1799}-504}{5}$$