Réitigh 60(1-t)^2=486

$$60 ( 1 - t ) ^ { 2 } = 486$$

Réitigh do t.

$$t=-\frac{9\sqrt{10}}{10}+1\approx -1.846049894$$

$$t=\frac{9\sqrt{10}}{10}+1\approx 3.846049894$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Roinn an dá thaobh faoi 60.

$$\frac{60\left(-t+1\right)^{2}}{60}=\frac{486}{60}$$

Má roinntear é faoi 60 cuirtear an iolrúchán faoi 60 ar ceal.

$$\left(-t+1\right)^{2}=\frac{486}{60}$$

Laghdaigh an codán \frac{486}{60} chuig na téarmaí is ísle trí 6 a bhaint agus a chealú.

$$\left(-t+1\right)^{2}=\frac{81}{10}$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$-t+1=\frac{9\sqrt{10}}{10} -t+1=-\frac{9\sqrt{10}}{10}$$

Bain 1 ón dá thaobh den chothromóid.

$$-t+1-1=\frac{9\sqrt{10}}{10}-1 -t+1-1=-\frac{9\sqrt{10}}{10}-1$$

Má dhealaítear 1 uaidh féin faightear 0.

$$-t=\frac{9\sqrt{10}}{10}-1 -t=-\frac{9\sqrt{10}}{10}-1$$

Dealaigh 1 ó \frac{9\sqrt{10}}{10}.

$$-t=\frac{9\sqrt{10}}{10}-1$$

Dealaigh 1 ó -\frac{9\sqrt{10}}{10}.

$$-t=-\frac{9\sqrt{10}}{10}-1$$

Roinn an dá thaobh faoi -1.

$$\frac{-t}{-1}=\frac{\frac{9\sqrt{10}}{10}-1}{-1} \frac{-t}{-1}=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Má roinntear é faoi -1 cuirtear an iolrúchán faoi -1 ar ceal.

$$t=\frac{\frac{9\sqrt{10}}{10}-1}{-1} t=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Roinn \frac{9\sqrt{10}}{10}-1 faoi -1.

$$t=-\frac{9\sqrt{10}}{10}+1$$

Roinn -\frac{9\sqrt{10}}{10}-1 faoi -1.

$$t=\frac{9\sqrt{10}}{10}+1$$

Tá an chothromóid réitithe anois.

$$t=-\frac{9\sqrt{10}}{10}+1 t=\frac{9\sqrt{10}}{10}+1$$