Réitigh 60(1-t)^2=48.6

$$60 ( 1 - t ) ^ { 2 } = 48.6$$

Réitigh do t.

$$t=0.1$$

$$t=1.9$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Roinn an dá thaobh faoi 60.

$$\frac{60\left(-t+1\right)^{2}}{60}=\frac{48.6}{60}$$

Má roinntear é faoi 60 cuirtear an iolrúchán faoi 60 ar ceal.

$$\left(-t+1\right)^{2}=\frac{48.6}{60}$$

Roinn 48.6 faoi 60.

$$\left(-t+1\right)^{2}=0.81$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$-t+1=\frac{9}{10} -t+1=-\frac{9}{10}$$

Bain 1 ón dá thaobh den chothromóid.

$$-t+1-1=\frac{9}{10}-1 -t+1-1=-\frac{9}{10}-1$$

Má dhealaítear 1 uaidh féin faightear 0.

$$-t=\frac{9}{10}-1 -t=-\frac{9}{10}-1$$

Dealaigh 1 ó \frac{9}{10}.

$$-t=-\frac{1}{10}$$

Dealaigh 1 ó -\frac{9}{10}.

$$-t=-\frac{19}{10}$$

Roinn an dá thaobh faoi -1.

$$\frac{-t}{-1}=-\frac{\frac{1}{10}}{-1} \frac{-t}{-1}=-\frac{\frac{19}{10}}{-1}$$

Má roinntear é faoi -1 cuirtear an iolrúchán faoi -1 ar ceal.

$$t=-\frac{\frac{1}{10}}{-1} t=-\frac{\frac{19}{10}}{-1}$$

Roinn -\frac{1}{10} faoi -1.

$$t=\frac{1}{10}$$

Roinn -\frac{19}{10} faoi -1.

$$t=\frac{19}{10}$$

Tá an chothromóid réitithe anois.

$$t=\frac{1}{10} t=\frac{19}{10}$$