Réitigh 50left(1-xright)^2=405

$$50 { \left(1-x \right) }^{ 2 } = 405$$

Réitigh do x.

$$x=-\frac{9\sqrt{10}}{10}+1\approx -1.846049894$$

$$x=\frac{9\sqrt{10}}{10}+1\approx 3.846049894$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Roinn an dá thaobh faoi 50.

$$\frac{50\left(-x+1\right)^{2}}{50}=\frac{405}{50}$$

Má roinntear é faoi 50 cuirtear an iolrúchán faoi 50 ar ceal.

$$\left(-x+1\right)^{2}=\frac{405}{50}$$

Laghdaigh an codán \frac{405}{50} chuig na téarmaí is ísle trí 5 a bhaint agus a chealú.

$$\left(-x+1\right)^{2}=\frac{81}{10}$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$-x+1=\frac{9\sqrt{10}}{10} -x+1=-\frac{9\sqrt{10}}{10}$$

Bain 1 ón dá thaobh den chothromóid.

$$-x+1-1=\frac{9\sqrt{10}}{10}-1 -x+1-1=-\frac{9\sqrt{10}}{10}-1$$

Má dhealaítear 1 uaidh féin faightear 0.

$$-x=\frac{9\sqrt{10}}{10}-1 -x=-\frac{9\sqrt{10}}{10}-1$$

Dealaigh 1 ó \frac{9\sqrt{10}}{10}.

$$-x=\frac{9\sqrt{10}}{10}-1$$

Dealaigh 1 ó -\frac{9\sqrt{10}}{10}.

$$-x=-\frac{9\sqrt{10}}{10}-1$$

Roinn an dá thaobh faoi -1.

$$\frac{-x}{-1}=\frac{\frac{9\sqrt{10}}{10}-1}{-1} \frac{-x}{-1}=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Má roinntear é faoi -1 cuirtear an iolrúchán faoi -1 ar ceal.

$$x=\frac{\frac{9\sqrt{10}}{10}-1}{-1} x=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Roinn \frac{9\sqrt{10}}{10}-1 faoi -1.

$$x=-\frac{9\sqrt{10}}{10}+1$$

Roinn -\frac{9\sqrt{10}}{10}-1 faoi -1.

$$x=\frac{9\sqrt{10}}{10}+1$$

Tá an chothromóid réitithe anois.

$$x=-\frac{9\sqrt{10}}{10}+1 x=\frac{9\sqrt{10}}{10}+1$$