Réitigh 450mm^2=(1/2)18mm(a+24mm)

$$450 mm ^ { 2 } = ( \frac { 1 } { 2 } ) 18 mm ( a + 24 mm )$$

Réitigh do a.

$$\left\{\begin{matrix}\\a=-2m\left(12m-25\right)\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&m=0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Chun cumhachtaí den bhonn céanna a iolrú, suimigh a n-easpónaint. Suimigh 1 agus 2 chun 3 a bhaint amach.

$$450m^{3}=\frac{1}{2}\times 18mm\left(a+24mm\right)$$

Méadaigh m agus m chun m^{2} a fháil.

$$450m^{3}=\frac{1}{2}\times 18mm\left(a+24m^{2}\right)$$

Méadaigh m agus m chun m^{2} a fháil.

$$450m^{3}=\frac{1}{2}\times 18m^{2}\left(a+24m^{2}\right)$$

Méadaigh \frac{1}{2} agus 18 chun 9 a fháil.

$$450m^{3}=9m^{2}\left(a+24m^{2}\right)$$

Úsáid an t-airí dáileach chun 9m^{2} a mhéadú faoi a+24m^{2}.

$$450m^{3}=9m^{2}a+216m^{4}$$

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$9m^{2}a+216m^{4}=450m^{3}$$

Bain 216m^{4} ón dá thaobh.

$$9m^{2}a=450m^{3}-216m^{4}$$

Roinn an dá thaobh faoi 9m^{2}.

$$\frac{9m^{2}a}{9m^{2}}=\frac{18\left(25-12m\right)m^{3}}{9m^{2}}$$

Má roinntear é faoi 9m^{2} cuirtear an iolrúchán faoi 9m^{2} ar ceal.

$$a=\frac{18\left(25-12m\right)m^{3}}{9m^{2}}$$

Roinn 18\left(25-12m\right)m^{3} faoi 9m^{2}.

$$a=2m\left(25-12m\right)$$

Réitigh do m.

$$\left\{\begin{matrix}\\m=0\text{, }&\text{unconditionally}\\m=\frac{-\sqrt{625-24a}+25}{24}\text{; }m=\frac{\sqrt{625-24a}+25}{24}\text{, }&a\leq \frac{625}{24}\end{matrix}\right.$$