Réitigh 3(x-4)^2=-6

$$3 ( x - 4 ) ^ { 2 } = - 6$$

Réitigh do x. (complex solution)

$$x=-\sqrt{2}i+4\approx 4-1.414213562i$$

$$x=4+\sqrt{2}i\approx 4+1.414213562i$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Má roinntear é faoi 3 cuirtear an iolrúchán faoi 3 ar ceal.

$$\left(x-4\right)^{2}=-\frac{6}{3}$$

Roinn -6 faoi 3.

$$\left(x-4\right)^{2}=-2$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$x-4=\sqrt{2}i x-4=-\sqrt{2}i$$

Cuir 4 leis an dá thaobh den chothromóid.

$$x-4-\left(-4\right)=\sqrt{2}i-\left(-4\right) x-4-\left(-4\right)=-\sqrt{2}i-\left(-4\right)$$

Má dhealaítear -4 uaidh féin faightear 0.

$$x=\sqrt{2}i-\left(-4\right) x=-\sqrt{2}i-\left(-4\right)$$

Dealaigh -4 ó i\sqrt{2}.

$$x=4+\sqrt{2}i$$

Dealaigh -4 ó -i\sqrt{2}.

$$x=-\sqrt{2}i+4$$

Tá an chothromóid réitithe anois.

$$x=4+\sqrt{2}i x=-\sqrt{2}i+4$$