Réitigh 3sqrt{3y-1}+sqrt[3]{1-2x}=0

$$3 \sqrt { 3 y - 1 } + \sqrt[ 3 ] { 1 - 2 x } = 0$$

Réitigh do y.

$$y=\frac{\left(1-2x\right)^{\frac{2}{3}}+9}{27}$$

$$x\geq \frac{1}{2}$$

Céimeanna chun cothromóidí fréimhe a réiteach

Bain \sqrt[3]{1-2x} ón dá thaobh den chothromóid.

$$3\sqrt{3y-1}+\sqrt[3]{1-2x}-\sqrt[3]{1-2x}=-\sqrt[3]{1-2x}$$

Má dhealaítear \sqrt[3]{1-2x} uaidh féin faightear 0.

$$3\sqrt{3y-1}=-\sqrt[3]{1-2x}$$

Roinn an dá thaobh faoi 3.

$$\frac{3\sqrt{3y-1}}{3}=-\frac{\sqrt[3]{1-2x}}{3}$$

Má roinntear é faoi 3 cuirtear an iolrúchán faoi 3 ar ceal.

$$\sqrt{3y-1}=-\frac{\sqrt[3]{1-2x}}{3}$$

Cearnaigh an dá thaobh den chothromóid.

$$3y-1=\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}$$

Cuir 1 leis an dá thaobh den chothromóid.

$$3y-1-\left(-1\right)=\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}-\left(-1\right)$$

Má dhealaítear -1 uaidh féin faightear 0.

$$3y=\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}-\left(-1\right)$$

Dealaigh -1 ó \frac{\left(1-2x\right)^{\frac{2}{3}}}{9}.

$$3y=\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}+1$$

Roinn an dá thaobh faoi 3.

$$\frac{3y}{3}=\frac{\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}+1}{3}$$

Má roinntear é faoi 3 cuirtear an iolrúchán faoi 3 ar ceal.

$$y=\frac{\frac{\left(1-2x\right)^{\frac{2}{3}}}{9}+1}{3}$$

Roinn \frac{\left(1-2x\right)^{\frac{2}{3}}}{9}+1 faoi 3.

$$y=\frac{\left(1-2x\right)^{\frac{2}{3}}}{27}+\frac{1}{3}$$

Réitigh do x.

$$x=\frac{81\sqrt{3y-1}y-27\sqrt{3y-1}+1}{2}$$

$$y\geq \frac{1}{3}$$