Réitigh 2m^2+6m^2=1

$$2 m ^ { 2 } + 6 m ^ { 2 } = 1$$

Réitigh do m.

$$m=\frac{\sqrt{2}}{4}\approx 0.353553391$$

$$m=-\frac{\sqrt{2}}{4}\approx -0.353553391$$

Céimeanna tríd an bhFréamh Chearnach a Fháil

Comhcheangail 2m^{2} agus 6m^{2} chun 8m^{2} a fháil.

$$8m^{2}=1$$

Roinn an dá thaobh faoi 8.

$$m^{2}=\frac{1}{8}$$

Tóg fréamh chearnach an dá thaobh den chothromóid.

$$m=\frac{\sqrt{2}}{4} m=-\frac{\sqrt{2}}{4}$$

Céimeanna ag Baint Úsáid as an bhFoirmle Chearnach

Comhcheangail 2m^{2} agus 6m^{2} chun 8m^{2} a fháil.

$$8m^{2}=1$$

Bain 1 ón dá thaobh.

$$8m^{2}-1=0$$

Tá an chothromóid seo i bhfoirm chaighdeánach: ax^{2}+bx+c=0. Cuir 8 in ionad a, 0 in ionad b, agus -1 in ionad c san fhoirmle chearnach, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\times 8\left(-1\right)}}{2\times 8}$$

Cearnóg 0.

$$m=\frac{0±\sqrt{-4\times 8\left(-1\right)}}{2\times 8}$$

Méadaigh -4 faoi 8.

$$m=\frac{0±\sqrt{-32\left(-1\right)}}{2\times 8}$$

Méadaigh -32 faoi -1.

$$m=\frac{0±\sqrt{32}}{2\times 8}$$

Tóg fréamh chearnach 32.

$$m=\frac{0±4\sqrt{2}}{2\times 8}$$

Méadaigh 2 faoi 8.

$$m=\frac{0±4\sqrt{2}}{16}$$

Réitigh an chothromóid m=\frac{0±4\sqrt{2}}{16} nuair is ionann ± agus plus.

$$m=\frac{\sqrt{2}}{4}$$

Réitigh an chothromóid m=\frac{0±4\sqrt{2}}{16} nuair is ionann ± agus míneas.

$$m=-\frac{\sqrt{2}}{4}$$

Tá an chothromóid réitithe anois.

$$m=\frac{\sqrt{2}}{4} m=-\frac{\sqrt{2}}{4}$$