Réitigh 2(x-1/3)^2+(1-1/9)}(2-1/3)=

$$2 ( x - \frac { 1 } { 3 } ) ^ { 2 } + ( 1 - \frac { 1 } { 9 } ) \} ( 2 - \frac { 1 } { 3 } ) =$$

Luacháil

$$\frac{2\left(\left(3x-1\right)^{2}+4\right)}{9}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(x-\frac{1}{3}\right)^{2} a leathnú.

$$2\left(x^{2}-\frac{2}{3}x+\frac{1}{9}\right)+1-\frac{1}{9}$$

Úsáid an t-airí dáileach chun 2 a mhéadú faoi x^{2}-\frac{2}{3}x+\frac{1}{9}.

$$2x^{2}-\frac{4}{3}x+\frac{2}{9}+1-\frac{1}{9}$$

Suimigh \frac{2}{9} agus 1 chun \frac{11}{9} a fháil.

$$2x^{2}-\frac{4}{3}x+\frac{11}{9}-\frac{1}{9}$$

Dealaigh \frac{1}{9} ó \frac{11}{9} chun \frac{10}{9} a fháil.

$$2x^{2}-\frac{4}{3}x+\frac{10}{9}$$

Fairsingigh

$$2x^{2}-\frac{4x}{3}+\frac{10}{9}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(x-\frac{1}{3}\right)^{2} a leathnú.

$$2\left(x^{2}-\frac{2}{3}x+\frac{1}{9}\right)+1-\frac{1}{9}$$

Úsáid an t-airí dáileach chun 2 a mhéadú faoi x^{2}-\frac{2}{3}x+\frac{1}{9}.

$$2x^{2}-\frac{4}{3}x+\frac{2}{9}+1-\frac{1}{9}$$

Suimigh \frac{2}{9} agus 1 chun \frac{11}{9} a fháil.

$$2x^{2}-\frac{4}{3}x+\frac{11}{9}-\frac{1}{9}$$

Dealaigh \frac{1}{9} ó \frac{11}{9} chun \frac{10}{9} a fháil.

$$2x^{2}-\frac{4}{3}x+\frac{10}{9}$$