Réitigh 2*((4*2^2-1/5*2^5)-(4*0^2-1/5*0^2))-?/5=

$$2 \times ( ( 4 \times 2 ^ { 2 } - \frac { 1 } { 5 } \times 2 ^ { 5 } ) - ( 4 \times 0 ^ { 2 } - \frac { 1 } { 5 } \times 0 ^ { 2 } ) ) - \frac { ? } { 5 } =$$

Luacháil

$$19$$

Céimeanna Réitigh

Ríomh cumhacht 2 de 2 agus faigh 4.

$$2\left(4\times 4-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Méadaigh 4 agus 4 chun 16 a fháil.

$$2\left(16-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Ríomh cumhacht 2 de 5 agus faigh 32.

$$2\left(16-\frac{1}{5}\times 32-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Méadaigh \frac{1}{5} agus 32 chun \frac{32}{5} a fháil.

$$2\left(16-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Coinbhéartaigh 16 i gcodán \frac{80}{5}.

$$2\left(\frac{80}{5}-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Tá an t-ainmneoir céanna ag \frac{80}{5} agus \frac{32}{5} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$2\left(\frac{80-32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Dealaigh 32 ó 80 chun 48 a fháil.

$$2\left(\frac{48}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Ríomh cumhacht 0 de 2 agus faigh 0.

$$2\left(\frac{48}{5}-\left(4\times 0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Méadaigh 4 agus 0 chun 0 a fháil.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Ríomh cumhacht 0 de 2 agus faigh 0.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0\right)\right)-\frac{1}{5}$$

Méadaigh \frac{1}{5} agus 0 chun 0 a fháil.

$$2\left(\frac{48}{5}-\left(0-0\right)\right)-\frac{1}{5}$$

Má dhealaítear 0 uaidh féin faightear 0.

$$2\left(\frac{48}{5}-0\right)-\frac{1}{5}$$

Dealaigh 0 ó \frac{48}{5} chun \frac{48}{5} a fháil.

$$2\times \frac{48}{5}-\frac{1}{5}$$

Scríobh 2\times \frac{48}{5} mar chodán aonair.

$$\frac{2\times 48}{5}-\frac{1}{5}$$

Méadaigh 2 agus 48 chun 96 a fháil.

$$\frac{96}{5}-\frac{1}{5}$$

Tá an t-ainmneoir céanna ag \frac{96}{5} agus \frac{1}{5} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{96-1}{5}$$

Dealaigh 1 ó 96 chun 95 a fháil.

$$\frac{95}{5}$$

Roinn 95 faoi 5 chun 19 a fháil.

$$19$$

Fachtóirigh

$$19$$