Réitigh 19a^3-12x+4=0

$$19 a ^ { 3 } - 12 x + 4 = 0$$

Réitigh do x.

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 19a^{3} ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

$$-12x+4=-19a^{3}$$

Bain 4 ón dá thaobh.

$$-12x=-19a^{3}-4$$

Roinn an dá thaobh faoi -12.

$$\frac{-12x}{-12}=\frac{-19a^{3}-4}{-12}$$

Má roinntear é faoi -12 cuirtear an iolrúchán faoi -12 ar ceal.

$$x=\frac{-19a^{3}-4}{-12}$$

Roinn -19a^{3}-4 faoi -12.

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

Réitigh do a. (complex solution)

$$a=\frac{19^{\frac{2}{3}}e^{\frac{2\pi i}{3}}\sqrt[3]{12x-4}}{19}$$

$$a=\frac{19^{\frac{2}{3}}\sqrt[3]{12x-4}}{19}$$

$$a=\frac{19^{\frac{2}{3}}e^{\frac{4\pi i}{3}}\sqrt[3]{12x-4}}{19}$$

Réitigh do a.

$$a=\frac{19^{\frac{2}{3}}\sqrt[3]{12x-4}}{19}$$