Réitigh 11x=9x/5y+13y

$$11x= \frac{ 9x }{ 5y } +13y$$

Réitigh do x.

$$x=\frac{65y^{2}}{55y-9}$$

$$y\neq \frac{9}{55}\text{ and }y\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Méadaigh an dá thaobh den chothromóid faoi 5y.

$$11x\times 5y=9x+13y\times 5y$$

Méadaigh 11 agus 5 chun 55 a fháil.

$$55xy=9x+13y\times 5y$$

Méadaigh y agus y chun y^{2} a fháil.

$$55xy=9x+13y^{2}\times 5$$

Méadaigh 13 agus 5 chun 65 a fháil.

$$55xy=9x+65y^{2}$$

Bain 9x ón dá thaobh.

$$55xy-9x=65y^{2}$$

Comhcheangail na téarmaí ar fad ina bhfuil x.

$$\left(55y-9\right)x=65y^{2}$$

Roinn an dá thaobh faoi 55y-9.

$$\frac{\left(55y-9\right)x}{55y-9}=\frac{65y^{2}}{55y-9}$$

Má roinntear é faoi 55y-9 cuirtear an iolrúchán faoi 55y-9 ar ceal.

$$x=\frac{65y^{2}}{55y-9}$$

Réitigh do y. (complex solution)

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\neq 0$$

Réitigh do y.

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\geq \frac{468}{605}\text{ or }x<0$$