Réitigh 1-6(2005+2(0-1)+2(0-1)+2(0-1)+2(0-1)/12)

$$1 - 6 ( 2005 + \frac { 2 ( 0 - 1 ) + 2 ( 0 - 1 ) + 2 ( 0 - 1 ) + 2 ( 0 - 1 ) } { 12 } )$$

Luacháil

$$-12025$$

Céimeanna Réitigh

Dealaigh 1 ó 0 chun -1 a fháil.

$$1-6\left(2005+\frac{2\left(-1\right)+2\left(0-1\right)+2\left(0-1\right)+2\left(0-1\right)}{12}\right)$$

Méadaigh 2 agus -1 chun -2 a fháil.

$$1-6\left(2005+\frac{-2+2\left(0-1\right)+2\left(0-1\right)+2\left(0-1\right)}{12}\right)$$

Dealaigh 1 ó 0 chun -1 a fháil.

$$1-6\left(2005+\frac{-2+2\left(-1\right)+2\left(0-1\right)+2\left(0-1\right)}{12}\right)$$

Méadaigh 2 agus -1 chun -2 a fháil.

$$1-6\left(2005+\frac{-2-2+2\left(0-1\right)+2\left(0-1\right)}{12}\right)$$

Dealaigh 2 ó -2 chun -4 a fháil.

$$1-6\left(2005+\frac{-4+2\left(0-1\right)+2\left(0-1\right)}{12}\right)$$

Dealaigh 1 ó 0 chun -1 a fháil.

$$1-6\left(2005+\frac{-4+2\left(-1\right)+2\left(0-1\right)}{12}\right)$$

Méadaigh 2 agus -1 chun -2 a fháil.

$$1-6\left(2005+\frac{-4-2+2\left(0-1\right)}{12}\right)$$

Dealaigh 2 ó -4 chun -6 a fháil.

$$1-6\left(2005+\frac{-6+2\left(0-1\right)}{12}\right)$$

Dealaigh 1 ó 0 chun -1 a fháil.

$$1-6\left(2005+\frac{-6+2\left(-1\right)}{12}\right)$$

Méadaigh 2 agus -1 chun -2 a fháil.

$$1-6\left(2005+\frac{-6-2}{12}\right)$$

Dealaigh 2 ó -6 chun -8 a fháil.

$$1-6\left(2005+\frac{-8}{12}\right)$$

Laghdaigh an codán \frac{-8}{12} chuig na téarmaí is ísle trí 4 a bhaint agus a chealú.

$$1-6\left(2005-\frac{2}{3}\right)$$

Coinbhéartaigh 2005 i gcodán \frac{6015}{3}.

$$1-6\left(\frac{6015}{3}-\frac{2}{3}\right)$$

Tá an t-ainmneoir céanna ag \frac{6015}{3} agus \frac{2}{3} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$1-6\times \frac{6015-2}{3}$$

Dealaigh 2 ó 6015 chun 6013 a fháil.

$$1-6\times \frac{6013}{3}$$

Scríobh 6\times \frac{6013}{3} mar chodán aonair.

$$1-\frac{6\times 6013}{3}$$

Méadaigh 6 agus 6013 chun 36078 a fháil.

$$1-\frac{36078}{3}$$

Roinn 36078 faoi 3 chun 12026 a fháil.

$$1-12026$$

Dealaigh 12026 ó 1 chun -12025 a fháil.

$$-12025$$

Fachtóirigh

$$-12025$$