Réitigh 1=b^2-4ac

$$1 = b ^ { 2 } - 4 a c$$

Réitigh do a.

$$\left\{\begin{matrix}a=\frac{b^{2}-1}{4c}\text{, }&c\neq 0\\a\in \mathrm{R}\text{, }&c=0\text{ and }|b|=1\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$b^{2}-4ac=1$$

Bain b^{2} ón dá thaobh.

$$-4ac=1-b^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-4c\right)a=1-b^{2}$$

Roinn an dá thaobh faoi -4c.

$$\frac{\left(-4c\right)a}{-4c}=\frac{1-b^{2}}{-4c}$$

Má roinntear é faoi -4c cuirtear an iolrúchán faoi -4c ar ceal.

$$a=\frac{1-b^{2}}{-4c}$$

Roinn -b^{2}+1 faoi -4c.

$$a=-\frac{1-b^{2}}{4c}$$

Réitigh do b.

$$b=\sqrt{4ac+1}$$

$$b=-\sqrt{4ac+1}\text{, }\left(c\leq 0\text{ or }a\geq -\frac{1}{4c}\right)\text{ and }\left(c\geq 0\text{ or }a\leq -\frac{1}{4c}\right)$$