Réitigh -b^2x^2+ax+4=0

$$- b ^ { 2 } x ^ { 2 } + a x + 4 = 0$$

Réitigh do a.

$$a=\frac{\left(bx\right)^{2}-4}{x}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain \left(-b^{2}\right)x^{2} ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

$$ax+4=-\left(-b^{2}\right)x^{2}$$

Bain 4 ón dá thaobh.

$$ax=-\left(-b^{2}\right)x^{2}-4$$

Méadaigh -1 agus -1 chun 1 a fháil.

$$ax=b^{2}x^{2}-4$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$xa=b^{2}x^{2}-4$$

Roinn an dá thaobh faoi x.

$$\frac{xa}{x}=\frac{b^{2}x^{2}-4}{x}$$

Má roinntear é faoi x cuirtear an iolrúchán faoi x ar ceal.

$$a=\frac{b^{2}x^{2}-4}{x}$$

Roinn b^{2}x^{2}-4 faoi x.

$$a=xb^{2}-\frac{4}{x}$$

Réitigh do b. (complex solution)

$$b=-\frac{\sqrt{ax+4}}{x}$$

$$b=\frac{\sqrt{ax+4}}{x}\text{, }x\neq 0$$

Réitigh do b.

$$b=\frac{\sqrt{ax+4}}{|x|}$$

$$b=-\frac{\sqrt{ax+4}}{|x|}\text{, }\left(a\neq 0\text{ and }x=-\frac{4}{a}\right)\text{ or }\left(x\leq -\frac{4}{a}\text{ and }a\leq 0\text{ and }x\neq 0\right)\text{ or }\left(a\geq 0\text{ and }x\geq -\frac{4}{a}\text{ and }x\neq 0\right)\text{ or }\left(a=0\text{ and }x\neq 0\right)$$