Réitigh -(2+2x^2)+(1/5x+5/4x^2+4/3)-(-2/3-frac{3}{4}x^2+frac{1}{5}x)

$$- ( 2 + 2 x ^ { 2 } ) + ( \frac { 1 } { 5 } x + \frac { 5 } { 4 } x ^ { 2 } + \frac { 4 } { 3 } ) - ( - \frac { 2 } { 3 } - \frac { 3 } { 4 } x ^ { 2 } + \frac { 1 } { 5 } x )$$

Luacháil

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Céimeanna Réitigh

Chun an mhalairt ar 2+2x^{2} a aimsiú, aimsigh an mhalairt ar gach téarma.

$$-2-2x^{2}+\frac{1}{5}x+\frac{5}{4}x^{2}+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Comhcheangail -2x^{2} agus \frac{5}{4}x^{2} chun -\frac{3}{4}x^{2} a fháil.

$$-2-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Suimigh -2 agus \frac{4}{3} chun -\frac{2}{3} a fháil.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Chun an mhalairt ar -\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x a aimsiú, aimsigh an mhalairt ar gach téarma.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{2}{3}+\frac{3}{4}x^{2}-\frac{1}{5}x$$

Suimigh -\frac{2}{3} agus \frac{2}{3} chun 0 a fháil.

$$-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{3}{4}x^{2}-\frac{1}{5}x$$

Comhcheangail -\frac{3}{4}x^{2} agus \frac{3}{4}x^{2} chun 0 a fháil.

$$\frac{1}{5}x-\frac{1}{5}x$$

Comhcheangail \frac{1}{5}x agus -\frac{1}{5}x chun 0 a fháil.

$$0$$

Fachtóirigh

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Céimeanna Réitigh

Fág \frac{1}{60} as an áireamh.

$$\frac{-120\left(1+x^{2}\right)+12x+75x^{2}+80-\left(-40-45x^{2}+12x\right)}{60}$$

Simpligh.

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