Réitigh -1/2left(z-1right)+1/2left(z+1right)-1/2left(z-1right)^2-1/2left(z+1right)

Luacháil

Fairsingigh

Tráth na gCeist

Polynomial

5 fadhbanna cosúil le:

Fadhbanna den chineál céanna ó Chuardach Gréasáin

https://www.tiger-algebra.com/drill/((z-1)/(z_1))~3-2$((z-1)/(z_1))~2_((z-1)/(z_1))-2=0/

https://math.stackexchange.com/questions/2407074/solving-frac-partial2-u-partial2-t-c2-w2-u

https://math.stackexchange.com/questions/1261515/dog-bone-contour-integral

https://math.stackexchange.com/q/529280

Roinn

Cóipeáladh go dtí an ghearrthaisce

-\frac{1}{2\left(z-1\right)}-\frac{1}{2\left(z-1\right)^{2}}

Dealaigh \frac{1}{2\left(z+1\right)} ó \frac{1}{2\left(z+1\right)} chun 0 a fháil.

-\frac{z-1}{2\left(z-1\right)^{2}}-\frac{1}{2\left(z-1\right)^{2}}

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de 2\left(z-1\right) agus 2\left(z-1\right)^{2} ná 2\left(z-1\right)^{2}. Méadaigh -\frac{1}{2\left(z-1\right)} faoi \frac{z-1}{z-1}.

\frac{-\left(z-1\right)-1}{2\left(z-1\right)^{2}}

Tá an t-ainmneoir céanna ag -\frac{z-1}{2\left(z-1\right)^{2}} agus \frac{1}{2\left(z-1\right)^{2}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

\frac{-z+1-1}{2\left(z-1\right)^{2}}

Déan iolrúcháin in -\left(z-1\right)-1.

\frac{-z}{2\left(z-1\right)^{2}}

Cumaisc téarmaí comhchosúla in: -z+1-1.

\frac{-z}{2z^{2}-4z+2}

Fairsingigh 2\left(z-1\right)^{2}