Réitigh do x.
x=\frac{\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)}{2}\approx -2.108880911
Réitigh do x. (complex solution)
x=\frac{\pi n_{1}i}{\ln(\frac{8}{3})}+\frac{\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)}{2}
n_{1}\in \mathrm{Z}
Graf
Tráth na gCeist
Algebra
5 fadhbanna cosúil le:
(45 \times 32) { \left( \frac{ 8 }{ 3 } \right) }^{ 2x } =23
Roinn
Cóipeáladh go dtí an ghearrthaisce
1440\times \left(\frac{8}{3}\right)^{2x}=23
Úsáid rialacha na n-easpónant agus na logartam chun an chothromóid a réiteach.
\left(\frac{8}{3}\right)^{2x}=\frac{23}{1440}
Roinn an dá thaobh faoi 1440.
\log(\left(\frac{8}{3}\right)^{2x})=\log(\frac{23}{1440})
Ghlac logartam an dá thaobh den chothromóid.
2x\log(\frac{8}{3})=\log(\frac{23}{1440})
Is ionann logartam uimhreacha a ardaítear go cumhacht agus an chumhacht méadaithe faoi logartam na huimhreach.
2x=\frac{\log(\frac{23}{1440})}{\log(\frac{8}{3})}
Roinn an dá thaobh faoi \log(\frac{8}{3}).
2x=\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)
Leis an bhfoirmle athrú boinn \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=\frac{\ln(\frac{23}{1440})}{2\ln(\frac{8}{3})}
Roinn an dá thaobh faoi 2.
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