Réitigh (n+7)^1/2 | Réiteoir Mata Microsoft

Difreálaigh w.r.t. n

Luacháil

Tráth na gCeist

Algebra

Fadhbanna den chineál céanna ó Chuardach Gréasáin

https://socratic.org/questions/how-do-you-write-2-3-1-8-in-logarithmic-form

https://socratic.org/questions/how-do-you-write-17-1-3-in-radical-form

https://math.stackexchange.com/q/1612298

https://math.stackexchange.com/questions/1899159/is-the-difference-of-two-irrationals-which-are-each-contained-under-a-single-squ

Roinn

Cóipeáladh go dtí an ghearrthaisce

\frac{1}{2}\left(n^{1}+7\right)^{\frac{1}{2}-1}\frac{\mathrm{d}}{\mathrm{d}n}(n^{1}+7)

Más F comhshuíomh dhá fheidhm indifreáilte f\left(u\right) agus u=g\left(x\right), is é sin, más F\left(x\right)=f\left(g\left(x\right)\right), mar sin is ionann díorthach F agus díorthach f maidir le u méadaithe faoi dhíorthach g maidir le x, is é sin, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

\frac{1}{2}\left(n^{1}+7\right)^{-\frac{1}{2}}n^{1-1}

Is ionann díorthach iltéarmaigh agus suim dhíorthaigh a théarmaí. Is ionann díorthach téarma thairisigh agus 0. Is ionann díorthach ax^{n} agus nax^{n-1}.

\frac{1}{2}n^{0}\left(n^{1}+7\right)^{-\frac{1}{2}}

Simpligh.

\frac{1}{2}n^{0}\left(n+7\right)^{-\frac{1}{2}}

Do théarma ar bith t, t^{1}=t.

\frac{1}{2}\times 1\left(n+7\right)^{-\frac{1}{2}}

Do théarma ar bith t ach amháin 0, t^{0}=1.

\frac{1}{2}\left(n+7\right)^{-\frac{1}{2}}

Do théarma ar bith t, t\times 1=t agus 1t=t.