Réitigh (fag)(x)=sqrt{x^2+4/3+x}

$$( f a g ) ( x ) = \sqrt { \frac { x ^ { 2 } + 4 } { 3 + x } }$$

Réitigh do a. (complex solution)

$$\left\{\begin{matrix}a=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{fgx}\text{, }&x\neq 0\text{ and }g\neq 0\text{ and }f\neq 0\text{ and }x\neq -3\\a\in \mathrm{C}\text{, }&\left(x=2i\text{ and }g=0\right)\text{ or }\left(x=-2i\text{ and }g=0\right)\text{ or }\left(f=0\text{ and }g\neq 0\text{ and }x=-2i\right)\text{ or }\left(f=0\text{ and }g\neq 0\text{ and }x=2i\right)\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Tá an chothromóid i bhfoirm chaighdeánach.

$$fgxa=\sqrt{\frac{x^{2}+4}{x+3}}$$

Roinn an dá thaobh faoi fgx.

$$\frac{fgxa}{fgx}=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{fgx}$$

Má roinntear é faoi fgx cuirtear an iolrúchán faoi fgx ar ceal.

$$a=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{fgx}$$

Réitigh do f. (complex solution)

$$\left\{\begin{matrix}f=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{agx}\text{, }&x\neq 0\text{ and }g\neq 0\text{ and }a\neq 0\text{ and }x\neq -3\\f\in \mathrm{C}\text{, }&\left(x=2i\text{ and }g=0\right)\text{ or }\left(x=-2i\text{ and }g=0\right)\text{ or }\left(a=0\text{ and }g\neq 0\text{ and }x=-2i\right)\text{ or }\left(a=0\text{ and }g\neq 0\text{ and }x=2i\right)\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Tá an chothromóid i bhfoirm chaighdeánach.

$$agxf=\sqrt{\frac{x^{2}+4}{x+3}}$$

Roinn an dá thaobh faoi agx.

$$\frac{agxf}{agx}=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{agx}$$

Má roinntear é faoi agx cuirtear an iolrúchán faoi agx ar ceal.

$$f=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{agx}$$

Réitigh do a.

$$a=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{fgx}$$

$$x\neq 0\text{ and }g\neq 0\text{ and }f\neq 0\text{ and }x>-3$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Tá an chothromóid i bhfoirm chaighdeánach.

$$fgxa=\sqrt{\frac{x^{2}+4}{x+3}}$$

Roinn an dá thaobh faoi fgx.

$$\frac{fgxa}{fgx}=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}fgx}$$

Má roinntear é faoi fgx cuirtear an iolrúchán faoi fgx ar ceal.

$$a=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}fgx}$$

Réitigh do f.

$$f=\frac{\sqrt{\frac{x^{2}+4}{x+3}}}{agx}$$

$$x\neq 0\text{ and }g\neq 0\text{ and }a\neq 0\text{ and }x>-3$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Tá an chothromóid i bhfoirm chaighdeánach.

$$agxf=\sqrt{\frac{x^{2}+4}{x+3}}$$

Roinn an dá thaobh faoi agx.

$$\frac{agxf}{agx}=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}agx}$$

Má roinntear é faoi agx cuirtear an iolrúchán faoi agx ar ceal.

$$f=\frac{\sqrt{x^{2}+4}}{\sqrt{x+3}agx}$$