Réitigh (a-1)x^2-x+1/4=0

$$( a - 1 ) x ^ { 2 } - x + \frac { 1 } { 4 } = 0$$

Réitigh do a.

$$a=1+\frac{1}{x}-\frac{1}{4x^{2}}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Úsáid an t-airí dáileach chun a-1 a mhéadú faoi x^{2}.

$$ax^{2}-x^{2}-x+\frac{1}{4}=0$$

Cuir x^{2} leis an dá thaobh. Is ionann rud ar bith móide nialas agus a shuim féin.

$$ax^{2}-x+\frac{1}{4}=x^{2}$$

Cuir x leis an dá thaobh.

$$ax^{2}+\frac{1}{4}=x^{2}+x$$

Bain \frac{1}{4} ón dá thaobh.

$$ax^{2}=x^{2}+x-\frac{1}{4}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$x^{2}a=x^{2}+x-\frac{1}{4}$$

Roinn an dá thaobh faoi x^{2}.

$$\frac{x^{2}a}{x^{2}}=\frac{x^{2}+x-\frac{1}{4}}{x^{2}}$$

Má roinntear é faoi x^{2} cuirtear an iolrúchán faoi x^{2} ar ceal.

$$a=\frac{x^{2}+x-\frac{1}{4}}{x^{2}}$$

Roinn x^{2}+x-\frac{1}{4} faoi x^{2}.

$$a=1+\frac{x-\frac{1}{4}}{x^{2}}$$

Réitigh do x.

$$\left\{\begin{matrix}x=\frac{\sqrt{2-a}+1}{2\left(a-1\right)}\text{; }x=\frac{-\sqrt{2-a}+1}{2\left(a-1\right)}\text{, }&a\neq 1\text{ and }a\leq 2\\x=\frac{1}{4}\text{, }&a=1\end{matrix}\right.$$