Réitigh (3sqrt{2}-sqrt{3})^2=

$$( 3 \sqrt { 2 } - \sqrt { 3 } ) ^ { 2 } =$$

Luacháil

$$21-6\sqrt{6}\approx 6.303061543$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(3\sqrt{2}-\sqrt{3}\right)^{2} a leathnú.

$$9\left(\sqrt{2}\right)^{2}-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$9\times 2-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Méadaigh 9 agus 2 chun 18 a fháil.

$$18-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{2} agus \sqrt{3} a iolrú.

$$18-6\sqrt{6}+\left(\sqrt{3}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$18-6\sqrt{6}+3$$

Suimigh 18 agus 3 chun 21 a fháil.

$$21-6\sqrt{6}$$

Fairsingigh

$$21-6\sqrt{6}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(3\sqrt{2}-\sqrt{3}\right)^{2} a leathnú.

$$9\left(\sqrt{2}\right)^{2}-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$9\times 2-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Méadaigh 9 agus 2 chun 18 a fháil.

$$18-6\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{2} agus \sqrt{3} a iolrú.

$$18-6\sqrt{6}+\left(\sqrt{3}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$18-6\sqrt{6}+3$$

Suimigh 18 agus 3 chun 21 a fháil.

$$21-6\sqrt{6}$$