Réitigh (sqrt{2}-1)^2+(sqrt{2}+1)^2

$$( \sqrt { 2 } - 1 ) ^ { 2 } + ( \sqrt { 2 } + 1 ) ^ { 2 }$$

Luacháil

$$6$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{2}-1\right)^{2} a leathnú.

$$\left(\sqrt{2}\right)^{2}-2\sqrt{2}+1+\left(\sqrt{2}+1\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$2-2\sqrt{2}+1+\left(\sqrt{2}+1\right)^{2}$$

Suimigh 2 agus 1 chun 3 a fháil.

$$3-2\sqrt{2}+\left(\sqrt{2}+1\right)^{2}$$

Úsáid an teoirim dhéthéarmach \left(a+b\right)^{2}=a^{2}+2ab+b^{2} chun \left(\sqrt{2}+1\right)^{2} a leathnú.

$$3-2\sqrt{2}+\left(\sqrt{2}\right)^{2}+2\sqrt{2}+1$$

Is é 2 uimhir chearnach \sqrt{2}.

$$3-2\sqrt{2}+2+2\sqrt{2}+1$$

Suimigh 2 agus 1 chun 3 a fháil.

$$3-2\sqrt{2}+3+2\sqrt{2}$$

Suimigh 3 agus 3 chun 6 a fháil.

$$6-2\sqrt{2}+2\sqrt{2}$$

Comhcheangail -2\sqrt{2} agus 2\sqrt{2} chun 0 a fháil.

$$6$$

Fachtóirigh

$$2\times 3$$