Réitigh (sqrt{2}-sqrt{3})^2

$$( \sqrt { 2 } - \sqrt { 3 } ) ^ { 2 }$$

Luacháil

$$5-2\sqrt{6}\approx 0.101020514$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{2}-\sqrt{3}\right)^{2} a leathnú.

$$\left(\sqrt{2}\right)^{2}-2\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$2-2\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{2} agus \sqrt{3} a iolrú.

$$2-2\sqrt{6}+\left(\sqrt{3}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$2-2\sqrt{6}+3$$

Suimigh 2 agus 3 chun 5 a fháil.

$$5-2\sqrt{6}$$

Fairsingigh

$$5-2\sqrt{6}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{2}-\sqrt{3}\right)^{2} a leathnú.

$$\left(\sqrt{2}\right)^{2}-2\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$2-2\sqrt{2}\sqrt{3}+\left(\sqrt{3}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{2} agus \sqrt{3} a iolrú.

$$2-2\sqrt{6}+\left(\sqrt{3}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$2-2\sqrt{6}+3$$

Suimigh 2 agus 3 chun 5 a fháil.

$$5-2\sqrt{6}$$