Réitigh (sqrt{10}-sqrt{2})^2

$$( \sqrt { 10 } - \sqrt { 2 } ) ^ { 2 }$$

Luacháil

$$12-4\sqrt{5}\approx 3.05572809$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{10}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 10 uimhir chearnach \sqrt{10}.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Fachtóirigh 10=2\times 5. Athscríobh fréamh cearnach an toraidh \sqrt{2\times 5} mar thoradh na bhfréamhacha cearnacha \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Méadaigh \sqrt{2} agus \sqrt{2} chun 2 a fháil.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Méadaigh -2 agus 2 chun -4 a fháil.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$10-4\sqrt{5}+2$$

Suimigh 10 agus 2 chun 12 a fháil.

$$12-4\sqrt{5}$$

Fairsingigh

$$12-4\sqrt{5}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{10}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 10 uimhir chearnach \sqrt{10}.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Fachtóirigh 10=2\times 5. Athscríobh fréamh cearnach an toraidh \sqrt{2\times 5} mar thoradh na bhfréamhacha cearnacha \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Méadaigh \sqrt{2} agus \sqrt{2} chun 2 a fháil.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Méadaigh -2 agus 2 chun -4 a fháil.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$10-4\sqrt{5}+2$$

Suimigh 10 agus 2 chun 12 a fháil.

$$12-4\sqrt{5}$$