Réitigh (frac{a^{2}}{a+B}-frac{a^{3}}{a^{2}+2aB+B^2}):(a/a+B-a^2/a^2-B^2)

$$( \frac { a ^ { 2 } } { a + B } - \frac { a ^ { 3 } } { a ^ { 2 } + 2 a B + B ^ { 2 } } ) : ( \frac { a } { a + B } - \frac { a ^ { 2 } } { a ^ { 2 } - B ^ { 2 } } )$$

Luacháil

$$-\frac{a\left(a-B\right)}{B+a}$$

Céimeanna gearra réitigh

Fachtóirigh a^{2}+2aB+B^{2}.

$$\frac{\frac{a^{2}}{a+B}-\frac{a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de a+B agus \left(B+a\right)^{2} ná \left(B+a\right)^{2}. Méadaigh \frac{a^{2}}{a+B} faoi \frac{B+a}{B+a}.

$$\frac{\frac{a^{2}\left(B+a\right)}{\left(B+a\right)^{2}}-\frac{a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Tá an t-ainmneoir céanna ag \frac{a^{2}\left(B+a\right)}{\left(B+a\right)^{2}} agus \frac{a^{3}}{\left(B+a\right)^{2}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\frac{a^{2}\left(B+a\right)-a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Déan iolrúcháin in a^{2}\left(B+a\right)-a^{3}.

$$\frac{\frac{a^{2}B+a^{3}-a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Cumaisc téarmaí comhchosúla in: a^{2}B+a^{3}-a^{3}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Fachtóirigh a^{2}-B^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de a+B agus \left(B+a\right)\left(-B+a\right) ná \left(B+a\right)\left(-B+a\right). Méadaigh \frac{a}{a+B} faoi \frac{-B+a}{-B+a}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a\left(-B+a\right)}{\left(B+a\right)\left(-B+a\right)}-\frac{a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Tá an t-ainmneoir céanna ag \frac{a\left(-B+a\right)}{\left(B+a\right)\left(-B+a\right)} agus \frac{a^{2}}{\left(B+a\right)\left(-B+a\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a\left(-B+a\right)-a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Déan iolrúcháin in a\left(-B+a\right)-a^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{-aB+a^{2}-a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Cumaisc téarmaí comhchosúla in: -aB+a^{2}-a^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{-aB}{\left(B+a\right)\left(-B+a\right)}}$$

Roinn \frac{a^{2}B}{\left(B+a\right)^{2}} faoi \frac{-aB}{\left(B+a\right)\left(-B+a\right)} trí \frac{a^{2}B}{\left(B+a\right)^{2}} a mhéadú faoi dheilín \frac{-aB}{\left(B+a\right)\left(-B+a\right)}.

$$\frac{a^{2}B\left(B+a\right)\left(-B+a\right)}{\left(B+a\right)^{2}\left(-1\right)aB}$$

Cealaigh Ba\left(B+a\right) mar uimhreoir agus ainmneoir.

$$\frac{a\left(-B+a\right)}{-\left(B+a\right)}$$

Úsáid an t-airí dáileach chun a a mhéadú faoi -B+a.

$$\frac{-aB+a^{2}}{-\left(B+a\right)}$$

Chun an mhalairt ar B+a a aimsiú, aimsigh an mhalairt ar gach téarma.

$$\frac{-aB+a^{2}}{-B-a}$$

Fairsingigh

$$-\frac{a^{2}-Ba}{B+a}$$

Céimeanna gearra réitigh

Fachtóirigh a^{2}+2aB+B^{2}.

$$\frac{\frac{a^{2}}{a+B}-\frac{a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de a+B agus \left(B+a\right)^{2} ná \left(B+a\right)^{2}. Méadaigh \frac{a^{2}}{a+B} faoi \frac{B+a}{B+a}.

$$\frac{\frac{a^{2}\left(B+a\right)}{\left(B+a\right)^{2}}-\frac{a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Tá an t-ainmneoir céanna ag \frac{a^{2}\left(B+a\right)}{\left(B+a\right)^{2}} agus \frac{a^{3}}{\left(B+a\right)^{2}} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\frac{a^{2}\left(B+a\right)-a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Déan iolrúcháin in a^{2}\left(B+a\right)-a^{3}.

$$\frac{\frac{a^{2}B+a^{3}-a^{3}}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Cumaisc téarmaí comhchosúla in: a^{2}B+a^{3}-a^{3}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{a^{2}-B^{2}}}$$

Fachtóirigh a^{2}-B^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a}{a+B}-\frac{a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Chun cothromóidí a shuimiú nó a dhealú, fairsingigh iad chun a n-ainmneoirí a mheaitseáil. Is é an t-iolrach is lú coitianta de a+B agus \left(B+a\right)\left(-B+a\right) ná \left(B+a\right)\left(-B+a\right). Méadaigh \frac{a}{a+B} faoi \frac{-B+a}{-B+a}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a\left(-B+a\right)}{\left(B+a\right)\left(-B+a\right)}-\frac{a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Tá an t-ainmneoir céanna ag \frac{a\left(-B+a\right)}{\left(B+a\right)\left(-B+a\right)} agus \frac{a^{2}}{\left(B+a\right)\left(-B+a\right)} agus, mar sin, is féidir iad a dhealú trína n-uimhreoirí a dhealú.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{a\left(-B+a\right)-a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Déan iolrúcháin in a\left(-B+a\right)-a^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{-aB+a^{2}-a^{2}}{\left(B+a\right)\left(-B+a\right)}}$$

Cumaisc téarmaí comhchosúla in: -aB+a^{2}-a^{2}.

$$\frac{\frac{a^{2}B}{\left(B+a\right)^{2}}}{\frac{-aB}{\left(B+a\right)\left(-B+a\right)}}$$

Roinn \frac{a^{2}B}{\left(B+a\right)^{2}} faoi \frac{-aB}{\left(B+a\right)\left(-B+a\right)} trí \frac{a^{2}B}{\left(B+a\right)^{2}} a mhéadú faoi dheilín \frac{-aB}{\left(B+a\right)\left(-B+a\right)}.

$$\frac{a^{2}B\left(B+a\right)\left(-B+a\right)}{\left(B+a\right)^{2}\left(-1\right)aB}$$

Cealaigh Ba\left(B+a\right) mar uimhreoir agus ainmneoir.

$$\frac{a\left(-B+a\right)}{-\left(B+a\right)}$$

Úsáid an t-airí dáileach chun a a mhéadú faoi -B+a.

$$\frac{-aB+a^{2}}{-\left(B+a\right)}$$

Chun an mhalairt ar B+a a aimsiú, aimsigh an mhalairt ar gach téarma.

$$\frac{-aB+a^{2}}{-B-a}$$