Réitigh y^2-8x-6y+25=0 | Réiteoir Mata Microsoft

Scipeáil chuig an bpríomhábhar

Réitigh do x.

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Réitigh do y. (complex solution)

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Réitigh do y.

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Graf

Tráth na gCeist

5 fadhbanna cosúil le:

Fadhbanna den chineál céanna ó Chuardach Gréasáin

https://socratic.org/questions/how-do-you-identity-if-the-equation-x-2-y-2-8x-6y-5-0-is-a-parabola-circle-ellip

https://socratic.org/questions/how-do-you-find-the-center-and-radius-of-the-circle-given-by-the-equation-x-2-y-

https://math.stackexchange.com/questions/798273/find-the-equations-of-the-circles-that-have-centre-0-0-and-touch-the-circle

https://socratic.org/questions/how-do-you-find-the-center-and-radius-of-the-circle-given-x-2-y-2-3x-8y-20

https://socratic.org/questions/how-do-you-find-the-standard-form-of-2y-2-x-8y-5-0-and-what-kind-of-a-conic-is-i

https://socratic.org/questions/how-do-you-write-the-equation-of-the-circle-in-standard-form-identify-the-center-1

Roinn

Cóipeáladh go dtí an ghearrthaisce

-8x-6y+25=-y^{2}

Bain y^{2} ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

-8x+25=-y^{2}+6y

Cuir 6y leis an dá thaobh.

-8x=-y^{2}+6y-25

Bain 25 ón dá thaobh.

\frac{-8x}{-8}=\frac{-y^{2}+6y-25}{-8}

Roinn an dá thaobh faoi -8.

x=\frac{-y^{2}+6y-25}{-8}

Má roinntear é faoi -8 cuirtear an iolrúchán faoi -8 ar ceal.

x=\frac{y^{2}}{8}-\frac{3y}{4}+\frac{25}{8}

Roinn -y^{2}+6y-25 faoi -8.

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