Réitigh v^2=u^2-2gh

$${ v }^{ 2 } = { u }^{ 2 } -2gh$$

Réitigh do g.

$$\left\{\begin{matrix}g=\frac{u^{2}-v^{2}}{2h}\text{, }&h\neq 0\\g\in \mathrm{R}\text{, }&h=0\text{ and }|v|=|u|\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$u^{2}-2gh=v^{2}$$

Bain u^{2} ón dá thaobh.

$$-2gh=v^{2}-u^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-2h\right)g=v^{2}-u^{2}$$

Roinn an dá thaobh faoi -2h.

$$\frac{\left(-2h\right)g}{-2h}=\frac{\left(v-u\right)\left(u+v\right)}{-2h}$$

Má roinntear é faoi -2h cuirtear an iolrúchán faoi -2h ar ceal.

$$g=\frac{\left(v-u\right)\left(u+v\right)}{-2h}$$

Roinn \left(v+u\right)\left(v-u\right) faoi -2h.

$$g=-\frac{\left(v-u\right)\left(u+v\right)}{2h}$$

Réitigh do h.

$$\left\{\begin{matrix}h=\frac{u^{2}-v^{2}}{2g}\text{, }&g\neq 0\\h\in \mathrm{R}\text{, }&g=0\text{ and }|v|=|u|\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$u^{2}-2gh=v^{2}$$

Bain u^{2} ón dá thaobh.

$$-2gh=v^{2}-u^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-2g\right)h=v^{2}-u^{2}$$

Roinn an dá thaobh faoi -2g.

$$\frac{\left(-2g\right)h}{-2g}=\frac{\left(v-u\right)\left(u+v\right)}{-2g}$$

Má roinntear é faoi -2g cuirtear an iolrúchán faoi -2g ar ceal.

$$h=\frac{\left(v-u\right)\left(u+v\right)}{-2g}$$

Roinn \left(v+u\right)\left(v-u\right) faoi -2g.

$$h=-\frac{\left(v-u\right)\left(u+v\right)}{2g}$$