Réitigh {left(sqrt{6}-sqrt{2}right)}^2=

$${ \left( \sqrt{ 6 } - \sqrt{ 2 } \right) }^{ 2 } =$$

Luacháil

$$8-4\sqrt{3}\approx 1.07179677$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{6}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{6}\right)^{2}-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 6 uimhir chearnach \sqrt{6}.

$$6-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Fachtóirigh 6=2\times 3. Athscríobh fréamh cearnach an toraidh \sqrt{2\times 3} mar thoradh na bhfréamhacha cearnacha \sqrt{2}\sqrt{3}.

$$6-2\sqrt{2}\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Méadaigh \sqrt{2} agus \sqrt{2} chun 2 a fháil.

$$6-2\times 2\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Méadaigh -2 agus 2 chun -4 a fháil.

$$6-4\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$6-4\sqrt{3}+2$$

Suimigh 6 agus 2 chun 8 a fháil.

$$8-4\sqrt{3}$$

Fairsingigh

$$8-4\sqrt{3}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{6}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{6}\right)^{2}-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 6 uimhir chearnach \sqrt{6}.

$$6-2\sqrt{6}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Fachtóirigh 6=2\times 3. Athscríobh fréamh cearnach an toraidh \sqrt{2\times 3} mar thoradh na bhfréamhacha cearnacha \sqrt{2}\sqrt{3}.

$$6-2\sqrt{2}\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Méadaigh \sqrt{2} agus \sqrt{2} chun 2 a fháil.

$$6-2\times 2\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Méadaigh -2 agus 2 chun -4 a fháil.

$$6-4\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$6-4\sqrt{3}+2$$

Suimigh 6 agus 2 chun 8 a fháil.

$$8-4\sqrt{3}$$