Réitigh {left(sqrt{3}-sqrt{2}right)}^2

$${ \left( \sqrt{ 3 } - \sqrt{ 2 } \right) }^{ 2 }$$

Luacháil

$$5-2\sqrt{6}\approx 0.101020514$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{3}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{3}\right)^{2}-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$3-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{3} agus \sqrt{2} a iolrú.

$$3-2\sqrt{6}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$3-2\sqrt{6}+2$$

Suimigh 3 agus 2 chun 5 a fháil.

$$5-2\sqrt{6}$$

Fairsingigh

$$5-2\sqrt{6}$$

Céimeanna Réitigh

Úsáid an teoirim dhéthéarmach \left(a-b\right)^{2}=a^{2}-2ab+b^{2} chun \left(\sqrt{3}-\sqrt{2}\right)^{2} a leathnú.

$$\left(\sqrt{3}\right)^{2}-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Is é 3 uimhir chearnach \sqrt{3}.

$$3-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Iolraigh na huimhreacha faoin bhfréamh cearnach chun \sqrt{3} agus \sqrt{2} a iolrú.

$$3-2\sqrt{6}+\left(\sqrt{2}\right)^{2}$$

Is é 2 uimhir chearnach \sqrt{2}.

$$3-2\sqrt{6}+2$$

Suimigh 3 agus 2 chun 5 a fháil.

$$5-2\sqrt{6}$$