Réitigh do x.
x=\frac{\sqrt{5513}y+67y+5\sqrt{5513}+431}{32}
Réitigh do y.
y=\frac{\sqrt{5513}x-67x+41-3\sqrt{5513}}{32}
Graf
Tráth na gCeist
Linear Equation
5 fadhbanna cosúil le:
\sqrt{ 37 } \left( 10x+7y+5 \right) = \sqrt{ 149 } ( \left( 6x-y-23 \right) )
Roinn
Cóipeáladh go dtí an ghearrthaisce
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}=\sqrt{149}\left(6x-y-23\right)
Úsáid an t-airí dáileach chun \sqrt{37} a mhéadú faoi 10x+7y+5.
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}=6\sqrt{149}x-\sqrt{149}y-23\sqrt{149}
Úsáid an t-airí dáileach chun \sqrt{149} a mhéadú faoi 6x-y-23.
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}-6\sqrt{149}x=-\sqrt{149}y-23\sqrt{149}
Bain 6\sqrt{149}x ón dá thaobh.
10\sqrt{37}x+5\sqrt{37}-6\sqrt{149}x=-\sqrt{149}y-23\sqrt{149}-7\sqrt{37}y
Bain 7\sqrt{37}y ón dá thaobh.
10\sqrt{37}x-6\sqrt{149}x=-\sqrt{149}y-23\sqrt{149}-7\sqrt{37}y-5\sqrt{37}
Bain 5\sqrt{37} ón dá thaobh.
\left(10\sqrt{37}-6\sqrt{149}\right)x=-\sqrt{149}y-23\sqrt{149}-7\sqrt{37}y-5\sqrt{37}
Comhcheangail na téarmaí ar fad ina bhfuil x.
\left(10\sqrt{37}-6\sqrt{149}\right)x=-7\sqrt{37}y-\sqrt{149}y-5\sqrt{37}-23\sqrt{149}
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(10\sqrt{37}-6\sqrt{149}\right)x}{10\sqrt{37}-6\sqrt{149}}=\frac{-7\sqrt{37}y-\sqrt{149}y-5\sqrt{37}-23\sqrt{149}}{10\sqrt{37}-6\sqrt{149}}
Roinn an dá thaobh faoi 10\sqrt{37}-6\sqrt{149}.
x=\frac{-7\sqrt{37}y-\sqrt{149}y-5\sqrt{37}-23\sqrt{149}}{10\sqrt{37}-6\sqrt{149}}
Má roinntear é faoi 10\sqrt{37}-6\sqrt{149} cuirtear an iolrúchán faoi 10\sqrt{37}-6\sqrt{149} ar ceal.
x=\frac{\frac{3\sqrt{149}+5\sqrt{37}}{416}\left(7\sqrt{37}y+\sqrt{149}y+5\sqrt{37}+23\sqrt{149}\right)}{2}
Roinn -\sqrt{149}y-23\sqrt{149}-7\sqrt{37}y-5\sqrt{37} faoi 10\sqrt{37}-6\sqrt{149}.
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}=\sqrt{149}\left(6x-y-23\right)
Úsáid an t-airí dáileach chun \sqrt{37} a mhéadú faoi 10x+7y+5.
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}=6\sqrt{149}x-\sqrt{149}y-23\sqrt{149}
Úsáid an t-airí dáileach chun \sqrt{149} a mhéadú faoi 6x-y-23.
10\sqrt{37}x+7\sqrt{37}y+5\sqrt{37}+\sqrt{149}y=6\sqrt{149}x-23\sqrt{149}
Cuir \sqrt{149}y leis an dá thaobh.
7\sqrt{37}y+5\sqrt{37}+\sqrt{149}y=6\sqrt{149}x-23\sqrt{149}-10\sqrt{37}x
Bain 10\sqrt{37}x ón dá thaobh.
7\sqrt{37}y+\sqrt{149}y=6\sqrt{149}x-23\sqrt{149}-10\sqrt{37}x-5\sqrt{37}
Bain 5\sqrt{37} ón dá thaobh.
\left(7\sqrt{37}+\sqrt{149}\right)y=6\sqrt{149}x-23\sqrt{149}-10\sqrt{37}x-5\sqrt{37}
Comhcheangail na téarmaí ar fad ina bhfuil y.
\left(\sqrt{149}+7\sqrt{37}\right)y=6\sqrt{149}x-10\sqrt{37}x-5\sqrt{37}-23\sqrt{149}
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(\sqrt{149}+7\sqrt{37}\right)y}{\sqrt{149}+7\sqrt{37}}=\frac{6\sqrt{149}x-10\sqrt{37}x-5\sqrt{37}-23\sqrt{149}}{\sqrt{149}+7\sqrt{37}}
Roinn an dá thaobh faoi 7\sqrt{37}+\sqrt{149}.
y=\frac{6\sqrt{149}x-10\sqrt{37}x-5\sqrt{37}-23\sqrt{149}}{\sqrt{149}+7\sqrt{37}}
Má roinntear é faoi 7\sqrt{37}+\sqrt{149} cuirtear an iolrúchán faoi 7\sqrt{37}+\sqrt{149} ar ceal.
y=\frac{\sqrt{5513}x-67x+41-3\sqrt{5513}}{32}
Roinn 6\sqrt{149}x-23\sqrt{149}-10\sqrt{37}x-5\sqrt{37} faoi 7\sqrt{37}+\sqrt{149}.
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