Réitigh sqrt[3]{9sqrt{3}-11sqrt{2}}=sqrt{3}+ksqrt{2}

$$\sqrt[ 3 ] { 9 \sqrt { 3 } - 11 \sqrt { 2 } } = \sqrt { 3 } + k \sqrt { 2 }$$

Réitigh do k.

$$k = -\frac{\sqrt{2} {(-\sqrt[3]{9 \sqrt{3} - 11 \sqrt{2}} + \sqrt{3})}}{2} \approx -1$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$\sqrt{3}+k\sqrt{2}=\sqrt[3]{9\sqrt{3}-11\sqrt{2}}$$

Bain \sqrt{3} ón dá thaobh.

$$k\sqrt{2}=\sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\sqrt{2}k=\sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3}$$

Roinn an dá thaobh faoi \sqrt{2}.

$$\frac{\sqrt{2}k}{\sqrt{2}}=\frac{\sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3}}{\sqrt{2}}$$

Má roinntear é faoi \sqrt{2} cuirtear an iolrúchán faoi \sqrt{2} ar ceal.

$$k=\frac{\sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3}}{\sqrt{2}}$$

Roinn \sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3} faoi \sqrt{2}.

$$k=\frac{\sqrt{2}\left(\sqrt[3]{9\sqrt{3}-11\sqrt{2}}-\sqrt{3}\right)}{2}$$