Réitigh operatorname{ph}5x+3y=15

$$\operatorname { ph } 5 x + 3 y = 15$$

Réitigh do h_5. (complex solution)

$$\left\{\begin{matrix}h_{5}=-\frac{3\left(y-5\right)}{px}\text{, }&x\neq 0\text{ and }p\neq 0\\h_{5}\in \mathrm{C}\text{, }&\left(x=0\text{ or }p=0\right)\text{ and }y=5\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 3y ón dá thaobh.

$$ph_{5}x=15-3y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$pxh_{5}=15-3y$$

Roinn an dá thaobh faoi px.

$$\frac{pxh_{5}}{px}=\frac{15-3y}{px}$$

Má roinntear é faoi px cuirtear an iolrúchán faoi px ar ceal.

$$h_{5}=\frac{15-3y}{px}$$

Roinn 15-3y faoi px.

$$h_{5}=\frac{3\left(5-y\right)}{px}$$

Réitigh do p. (complex solution)

$$\left\{\begin{matrix}p=-\frac{3\left(y-5\right)}{h_{5}x}\text{, }&x\neq 0\text{ and }h_{5}\neq 0\\p\in \mathrm{C}\text{, }&\left(x=0\text{ or }h_{5}=0\right)\text{ and }y=5\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 3y ón dá thaobh.

$$ph_{5}x=15-3y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$h_{5}xp=15-3y$$

Roinn an dá thaobh faoi h_{5}x.

$$\frac{h_{5}xp}{h_{5}x}=\frac{15-3y}{h_{5}x}$$

Má roinntear é faoi h_{5}x cuirtear an iolrúchán faoi h_{5}x ar ceal.

$$p=\frac{15-3y}{h_{5}x}$$

Roinn 15-3y faoi h_{5}x.

$$p=\frac{3\left(5-y\right)}{h_{5}x}$$

Réitigh do h_5.

$$\left\{\begin{matrix}h_{5}=-\frac{3\left(y-5\right)}{px}\text{, }&x\neq 0\text{ and }p\neq 0\\h_{5}\in \mathrm{R}\text{, }&\left(x=0\text{ or }p=0\right)\text{ and }y=5\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 3y ón dá thaobh.

$$ph_{5}x=15-3y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$pxh_{5}=15-3y$$

Roinn an dá thaobh faoi px.

$$\frac{pxh_{5}}{px}=\frac{15-3y}{px}$$

Má roinntear é faoi px cuirtear an iolrúchán faoi px ar ceal.

$$h_{5}=\frac{15-3y}{px}$$

Roinn 15-3y faoi px.

$$h_{5}=\frac{3\left(5-y\right)}{px}$$

Réitigh do p.

$$\left\{\begin{matrix}p=-\frac{3\left(y-5\right)}{h_{5}x}\text{, }&x\neq 0\text{ and }h_{5}\neq 0\\p\in \mathrm{R}\text{, }&\left(x=0\text{ or }h_{5}=0\right)\text{ and }y=5\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 3y ón dá thaobh.

$$ph_{5}x=15-3y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$h_{5}xp=15-3y$$

Roinn an dá thaobh faoi h_{5}x.

$$\frac{h_{5}xp}{h_{5}x}=\frac{15-3y}{h_{5}x}$$

Má roinntear é faoi h_{5}x cuirtear an iolrúchán faoi h_{5}x ar ceal.

$$p=\frac{15-3y}{h_{5}x}$$

Roinn 15-3y faoi h_{5}x.

$$p=\frac{3\left(5-y\right)}{h_{5}x}$$