Réitigh operatorname{gen}20x+40y=400

$$\operatorname { gen } 20 x + 40 y = 400$$

Réitigh do g. (complex solution)

$$\left\{\begin{matrix}g=-\frac{40\left(y-10\right)}{en_{20}x}\text{, }&x\neq 0\text{ and }n_{20}\neq 0\\g\in \mathrm{C}\text{, }&\left(n_{20}=0\text{ or }x=0\right)\text{ and }y=10\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 40y ón dá thaobh.

$$gen_{20}x=400-40y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$en_{20}xg=400-40y$$

Roinn an dá thaobh faoi en_{20}x.

$$\frac{en_{20}xg}{en_{20}x}=\frac{400-40y}{en_{20}x}$$

Má roinntear é faoi en_{20}x cuirtear an iolrúchán faoi en_{20}x ar ceal.

$$g=\frac{400-40y}{en_{20}x}$$

Roinn 400-40y faoi en_{20}x.

$$g=\frac{40\left(10-y\right)}{en_{20}x}$$

Réitigh do n_20. (complex solution)

$$\left\{\begin{matrix}n_{20}=-\frac{40\left(y-10\right)}{egx}\text{, }&x\neq 0\text{ and }g\neq 0\\n_{20}\in \mathrm{C}\text{, }&\left(x=0\text{ or }g=0\right)\text{ and }y=10\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 40y ón dá thaobh.

$$gen_{20}x=400-40y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$egxn_{20}=400-40y$$

Roinn an dá thaobh faoi gex.

$$\frac{egxn_{20}}{egx}=\frac{400-40y}{egx}$$

Má roinntear é faoi gex cuirtear an iolrúchán faoi gex ar ceal.

$$n_{20}=\frac{400-40y}{egx}$$

Roinn 400-40y faoi gex.

$$n_{20}=\frac{40\left(10-y\right)}{egx}$$

Réitigh do g.

$$\left\{\begin{matrix}g=-\frac{40\left(y-10\right)}{en_{20}x}\text{, }&x\neq 0\text{ and }n_{20}\neq 0\\g\in \mathrm{R}\text{, }&\left(n_{20}=0\text{ or }x=0\right)\text{ and }y=10\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 40y ón dá thaobh.

$$gen_{20}x=400-40y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$en_{20}xg=400-40y$$

Roinn an dá thaobh faoi en_{20}x.

$$\frac{en_{20}xg}{en_{20}x}=\frac{400-40y}{en_{20}x}$$

Má roinntear é faoi en_{20}x cuirtear an iolrúchán faoi en_{20}x ar ceal.

$$g=\frac{400-40y}{en_{20}x}$$

Roinn 400-40y faoi en_{20}x.

$$g=\frac{40\left(10-y\right)}{en_{20}x}$$

Réitigh do n_20.

$$\left\{\begin{matrix}n_{20}=-\frac{40\left(y-10\right)}{egx}\text{, }&x\neq 0\text{ and }g\neq 0\\n_{20}\in \mathrm{R}\text{, }&\left(x=0\text{ or }g=0\right)\text{ and }y=10\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 40y ón dá thaobh.

$$gen_{20}x=400-40y$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$egxn_{20}=400-40y$$

Roinn an dá thaobh faoi gex.

$$\frac{egxn_{20}}{egx}=\frac{400-40y}{egx}$$

Má roinntear é faoi gex cuirtear an iolrúchán faoi gex ar ceal.

$$n_{20}=\frac{400-40y}{egx}$$

Roinn 400-40y faoi gex.

$$n_{20}=\frac{40\left(10-y\right)}{egx}$$