Réitigh do x. (complex solution)
\left\{\begin{matrix}x=\frac{a+b}{3}\text{, }&b=-a\text{ or }b=-a+\frac{\sqrt{9-24a}}{2}+\frac{3}{2}\text{ or }b=-a-\frac{\sqrt{9-24a}}{2}+\frac{3}{2}\text{ or }b=a-3\\x=-\frac{b}{2}\text{, }&b=-\sqrt{-\frac{\sqrt{\left(a+2\right)^{2}\left(a^{2}+12a+4\right)}}{2}+\frac{a^{2}}{2}+4a+2}\text{ or }b=\sqrt{-\frac{\sqrt{\left(a+2\right)^{2}\left(a^{2}+12a+4\right)}}{2}+\frac{a^{2}}{2}+4a+2}\text{ or }b=-\sqrt{\frac{\sqrt{\left(a+2\right)^{2}\left(a^{2}+12a+4\right)}}{2}+\frac{a^{2}}{2}+4a+2}\text{ or }b=\sqrt{\frac{\sqrt{\left(a+2\right)^{2}\left(a^{2}+12a+4\right)}}{2}+\frac{a^{2}}{2}+4a+2}\end{matrix}\right.
Réitigh do x.
\left\{\begin{matrix}x=\frac{a+b}{3}\text{, }&b=-a\text{ or }\left(b=-a+\frac{\sqrt{9-24a}}{2}+\frac{3}{2}\text{ and }a\leq \frac{3}{8}\right)\text{ or }\left(b=-a-\frac{\sqrt{9-24a}}{2}+\frac{3}{2}\text{ and }a\leq \frac{3}{8}\right)\text{ or }b=a-3\\x=-\frac{b}{2}\text{, }&\left(a\leq -4\sqrt{2}-6\text{ and }2a\sqrt{a^{2}+12a+4}+2a^{2}+4\sqrt{a^{2}+12a+4}+16a\geq -8\text{ and }|b|=\frac{\sqrt{2a\sqrt{a^{2}+12a+4}+2a^{2}+4\sqrt{a^{2}+12a+4}+16a+8}}{2}\right)\text{ or }\left(a\geq 4\sqrt{2}-6\text{ and }2a\sqrt{a^{2}+12a+4}+2a^{2}+4\sqrt{a^{2}+12a+4}+16a\geq -8\text{ and }|b|=\frac{\sqrt{2a\sqrt{a^{2}+12a+4}+2a^{2}+4\sqrt{a^{2}+12a+4}+16a+8}}{2}\right)\text{ or }\left(a=4\sqrt{2}-6\text{ and }|b|=2\sqrt{2}-2\right)\text{ or }\left(a=-4\sqrt{2}-6\text{ and }|b|=2\sqrt{2}+2\right)\text{ or }\left(a\leq -4\sqrt{2}-6\text{ and }-2a\sqrt{a^{2}+12a+4}+2a^{2}-4\sqrt{a^{2}+12a+4}+16a\geq -8\text{ and }|b|=\frac{\sqrt{-2a\sqrt{a^{2}+12a+4}+2a^{2}-4\sqrt{a^{2}+12a+4}+16a+8}}{2}\right)\text{ or }\left(a\geq 4\sqrt{2}-6\text{ and }-2a\sqrt{a^{2}+12a+4}+2a^{2}-4\sqrt{a^{2}+12a+4}+16a\geq -8\text{ and }|b|=\frac{\sqrt{-2a\sqrt{a^{2}+12a+4}+2a^{2}-4\sqrt{a^{2}+12a+4}+16a+8}}{2}\right)\end{matrix}\right.
Graf
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