Scipeáil chuig an bpríomhábhar
Réitigh do U_1,U_2,I_x.
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Fadhbanna den chineál céanna ó Chuardach Gréasáin

Roinn

I_{x}=\frac{1}{3} \frac{1}{4}U_{2}+\left(U_{2}-U_{1}\right)\times \frac{1}{2}+5I_{x}=0 \left(U_{1}-U_{2}\right)\times \frac{1}{2}+\frac{1}{10}U_{1}+5I_{x}=2
Athraigh ord na gcothromóidí.
\frac{1}{4}U_{2}+\left(U_{2}-U_{1}\right)\times \frac{1}{2}+5\times \frac{1}{3}=0 \left(U_{1}-U_{2}\right)\times \frac{1}{2}+\frac{1}{10}U_{1}+5\times \frac{1}{3}=2
Cuir \frac{1}{3} in ionad I_{x} sa dara agus sa tríú cothromóid.
U_{2}=-\frac{20}{9}+\frac{2}{3}U_{1} U_{1}=\frac{5}{9}+\frac{5}{6}U_{2}
Réitigh na cothromóidí seo do U_{2} agus U_{1} faoi seach.
U_{1}=\frac{5}{9}+\frac{5}{6}\left(-\frac{20}{9}+\frac{2}{3}U_{1}\right)
Cuir -\frac{20}{9}+\frac{2}{3}U_{1} in ionad U_{2} sa chothromóid U_{1}=\frac{5}{9}+\frac{5}{6}U_{2}.
U_{1}=-\frac{35}{12}
Réitigh U_{1}=\frac{5}{9}+\frac{5}{6}\left(-\frac{20}{9}+\frac{2}{3}U_{1}\right) do U_{1}.
U_{2}=-\frac{20}{9}+\frac{2}{3}\left(-\frac{35}{12}\right)
Cuir -\frac{35}{12} in ionad U_{1} sa chothromóid U_{2}=-\frac{20}{9}+\frac{2}{3}U_{1}.
U_{2}=-\frac{25}{6}
Ríomh U_{2} ó U_{2}=-\frac{20}{9}+\frac{2}{3}\left(-\frac{35}{12}\right).
U_{1}=-\frac{35}{12} U_{2}=-\frac{25}{6} I_{x}=\frac{1}{3}
Tá an córas réitithe anois.