Réitigh do P. (complex solution)
\left\{\begin{matrix}\\P=0\text{, }&\text{unconditionally}\\P\in \mathrm{C}\text{, }&10p^{2.2}+12527p+957500=0\text{ and }p\neq 0\end{matrix}\right.
Réitigh do P.
\left\{\begin{matrix}\\P=0\text{, }&\text{unconditionally}\\P\in \mathrm{R}\text{, }&10p^{2.2}+12527p+957500=0\text{ and }p\neq 0\end{matrix}\right.
Tráth na gCeist
Linear Equation
5 fadhbanna cosúil le:
\left( 173-47.73+0.1 { p }^{ 1.2 } + \frac{ 1750+7825 }{ p } \right) P = 0
Roinn
Cóipeáladh go dtí an ghearrthaisce
\left(173-47.73+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0
Méadaigh an dá thaobh den chothromóid faoi p.
\left(125.27+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0
Dealaigh 47.73 ó 173 chun 125.27 a fháil.
\left(125.27+0.1p^{1.2}+\frac{9575}{p}\right)Pp=0
Suimigh 1750 agus 7825 chun 9575 a fháil.
\left(125.27P+0.1p^{1.2}P+\frac{9575}{p}P\right)p=0
Úsáid an t-airí dáileach chun 125.27+0.1p^{1.2}+\frac{9575}{p} a mhéadú faoi P.
\left(125.27P+0.1p^{1.2}P+\frac{9575P}{p}\right)p=0
Scríobh \frac{9575}{p}P mar chodán aonair.
125.27Pp+0.1p^{1.2}Pp+\frac{9575P}{p}p=0
Úsáid an t-airí dáileach chun 125.27P+0.1p^{1.2}P+\frac{9575P}{p} a mhéadú faoi p.
125.27Pp+0.1p^{2.2}P+\frac{9575P}{p}p=0
Chun cumhachtaí den bhonn céanna a iolrú, suimigh a n-easpónaint. Suimigh 1.2 agus 1 chun 2.2 a bhaint amach.
125.27Pp+0.1p^{2.2}P+\frac{9575Pp}{p}=0
Scríobh \frac{9575P}{p}p mar chodán aonair.
125.27Pp+0.1p^{2.2}P+9575P=0
Cealaigh p mar uimhreoir agus ainmneoir.
\left(125.27p+0.1p^{2.2}+9575\right)P=0
Comhcheangail na téarmaí ar fad ina bhfuil P.
\left(\frac{p^{2.2}}{10}+\frac{12527p}{100}+9575\right)P=0
Tá an chothromóid i bhfoirm chaighdeánach.
P=0
Roinn 0 faoi 125.27p+0.1p^{2.2}+9575.
\left(173-47.73+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0
Méadaigh an dá thaobh den chothromóid faoi p.
\left(125.27+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0
Dealaigh 47.73 ó 173 chun 125.27 a fháil.
\left(125.27+0.1p^{1.2}+\frac{9575}{p}\right)Pp=0
Suimigh 1750 agus 7825 chun 9575 a fháil.
\left(125.27P+0.1p^{1.2}P+\frac{9575}{p}P\right)p=0
Úsáid an t-airí dáileach chun 125.27+0.1p^{1.2}+\frac{9575}{p} a mhéadú faoi P.
\left(125.27P+0.1p^{1.2}P+\frac{9575P}{p}\right)p=0
Scríobh \frac{9575}{p}P mar chodán aonair.
125.27Pp+0.1p^{1.2}Pp+\frac{9575P}{p}p=0
Úsáid an t-airí dáileach chun 125.27P+0.1p^{1.2}P+\frac{9575P}{p} a mhéadú faoi p.
125.27Pp+0.1p^{2.2}P+\frac{9575P}{p}p=0
Chun cumhachtaí den bhonn céanna a iolrú, suimigh a n-easpónaint. Suimigh 1.2 agus 1 chun 2.2 a bhaint amach.
125.27Pp+0.1p^{2.2}P+\frac{9575Pp}{p}=0
Scríobh \frac{9575P}{p}p mar chodán aonair.
125.27Pp+0.1p^{2.2}P+9575P=0
Cealaigh p mar uimhreoir agus ainmneoir.
\left(125.27p+0.1p^{2.2}+9575\right)P=0
Comhcheangail na téarmaí ar fad ina bhfuil P.
\left(\frac{p^{2.2}}{10}+\frac{12527p}{100}+9575\right)P=0
Tá an chothromóid i bhfoirm chaighdeánach.
P=0
Roinn 0 faoi 125.27p+0.1p^{2.2}+9575.
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