Scipeáil chuig an bpríomhábhar
Réitigh do x_1,x_2,x_3.
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Fadhbanna den chineál céanna ó Chuardach Gréasáin

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x_{1}=x_{2}-x_{3}+2
Réitigh x_{1}-x_{2}+x_{3}=2 do x_{1}.
x_{2}-x_{3}+2+2x_{2}=1 x_{2}-x_{3}+2-x_{3}=4
Cuir x_{2}-x_{3}+2 in ionad x_{1} sa dara agus sa tríú cothromóid.
x_{2}=-\frac{1}{3}+\frac{1}{3}x_{3} x_{3}=-1+\frac{1}{2}x_{2}
Réitigh na cothromóidí seo do x_{2} agus x_{3} faoi seach.
x_{3}=-1+\frac{1}{2}\left(-\frac{1}{3}+\frac{1}{3}x_{3}\right)
Cuir -\frac{1}{3}+\frac{1}{3}x_{3} in ionad x_{2} sa chothromóid x_{3}=-1+\frac{1}{2}x_{2}.
x_{3}=-\frac{7}{5}
Réitigh x_{3}=-1+\frac{1}{2}\left(-\frac{1}{3}+\frac{1}{3}x_{3}\right) do x_{3}.
x_{2}=-\frac{1}{3}+\frac{1}{3}\left(-\frac{7}{5}\right)
Cuir -\frac{7}{5} in ionad x_{3} sa chothromóid x_{2}=-\frac{1}{3}+\frac{1}{3}x_{3}.
x_{2}=-\frac{4}{5}
Ríomh x_{2} ó x_{2}=-\frac{1}{3}+\frac{1}{3}\left(-\frac{7}{5}\right).
x_{1}=-\frac{4}{5}-\left(-\frac{7}{5}\right)+2
Cuir -\frac{4}{5} in ionad x_{2} agus -\frac{7}{5} in ionad x_{3} sa chothromóid x_{1}=x_{2}-x_{3}+2.
x_{1}=\frac{13}{5}
Ríomh x_{1} ó x_{1}=-\frac{4}{5}-\left(-\frac{7}{5}\right)+2.
x_{1}=\frac{13}{5} x_{2}=-\frac{4}{5} x_{3}=-\frac{7}{5}
Tá an córas réitithe anois.