Réitigh ∫ t^2gdg

$$\int t ^ { 2 } g d g$$

Luacháil

$$\frac{\left(gt\right)^{2}}{2}+С$$

Céimeanna Réitigh

Fág an úsáid leanúnach do\int af\left(g\right)\mathrm{d}g=a\int f\left(g\right)\mathrm{d}g as an áireamh.

$$t^{2}\int g\mathrm{d}g$$

Ó \int g^{k}\mathrm{d}g=\frac{g^{k+1}}{k+1} fá choinne k\neq -1, athchuir \int g\mathrm{d}g le \frac{g^{2}}{2}.

$$t^{2}\times \frac{g^{2}}{2}$$

Simpligh.

$$\frac{t^{2}g^{2}}{2}$$

Má tá F\left(g\right) mar frithdhíorthach do f\left(g\right), beidh tacar do frithdhíorthach uile do f\left(g\right) a thabhairt ag F\left(g\right)+C. Mar sin de, cur an comhtháthú leanúnach C\in \mathrm{R} don toradh.

$$\frac{t^{2}g^{2}}{2}+С$$

Difreálaigh w.r.t. t

$$tg^{2}$$